Xoring字母与空格字符 [英] Xoring alphabet letters with space character

问题描述

是否有历史原因可以解释为什么用空格字符对任何字母进行异或运算会改变字母的大小写?(即'a'xor''='A'，'F'xor''='f'，等等...)

Is there a historical reason as to why Xoring any alphabetic letter with the space character changes the case of the letter? (i.e., 'a' xor ' ' = 'A', 'F' xor ' ' = 'f', etc...)

或者这仅仅是一个巧合吗?

Or is this just a coincidence?

(假设字符是ASCII或unicode编码的.)

(Assuming the characters are ASCII- or unicode-encoded.)

推荐答案

我确信可以通过更改一点来更改大小写，这将使早期的软件更加有效.空格字符为#32的事实是无关紧要的.

I'm sure it was deliberate that the case could be changed by changing a single bit - it will have made early software much more efficient. The fact that the space character is #32 is irrelevant.

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