如何使用 Python 读取 URL 的内容? [英] How can I read the contents of an URL with Python?

问题描述

当我将其粘贴到浏览器上时，以下内容有效:

The following works when I paste it on the browser:

http://www.somesite.com/details.pl?urn=2344

但是当我尝试使用 Python 读取 URL 时，没有任何反应:

But when I try reading the URL with Python nothing happens:

 link = 'http://www.somesite.com/details.pl?urn=2344'
 f = urllib.urlopen(link)           
 myfile = f.readline()  
 print myfile

我是否需要对 URL 进行编码，或者有什么我没有看到的内容?

Do I need to encode the URL, or is there something I'm not seeing?

推荐答案

回答您的问题:

import urllib

link = "http://www.somesite.com/details.pl?urn=2344"
f = urllib.urlopen(link)
myfile = f.read()
print(myfile)

你需要read()，而不是readline()

EDIT (2018-06-25):从 Python 3 开始，遗留的 urllib.urlopen() 被 urllib.request.urlopen() 取代(见注释来自 https://docs.python.org/3/library/urllib.request.html#urllib.request.urlopen 详情).

EDIT (2018-06-25): Since Python 3, the legacy urllib.urlopen() was replaced by urllib.request.urlopen() (see notes from https://docs.python.org/3/library/urllib.request.html#urllib.request.urlopen for details).

如果您使用的是 Python 3，请参阅 Martin Thoma 或 i.n.n.m 在此问题中的回答:https://stackoverflow.com/a/28040508/158111(Python 2/3 兼容)https://stackoverflow.com/a/45886824/158111(Python 3)

If you're using Python 3, see answers by Martin Thoma or i.n.n.m within this question: https://stackoverflow.com/a/28040508/158111 (Python 2/3 compat) https://stackoverflow.com/a/45886824/158111 (Python 3)

或者，只需在此处获取此库:http://docs.python-requests.org/en/latest/ 并认真使用它:)

Or, just get this library here: http://docs.python-requests.org/en/latest/ and seriously use it :)

import requests

link = "http://www.somesite.com/details.pl?urn=2344"
f = requests.get(link)
print(f.text)

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