排序数字文件在bash [英] Sort files numerically in bash

问题描述

我需要数字排序。FLV文件，我能够用下面的命令来做到这一点：

  LS * \\ FLV |排序--version排序-f
 

但有很多文件（数百）这不是正确排序

  LS * \\ FLV |排序--version排序-f |尾-n 20
e680.flv
e681.flv
e682.flv
e683.flv
e684.flv
e685.flv
e686.flv
e687.flv
e688.flv
e689.flv
e690.flv
e691.flv
e692.flv
e693.flv
e694.flv
e695.flv
** ** e696.flv
s572.flv
s602.flv
s654.flv
 

但奇怪的是这样的，如果我搞坏了命令而不*。FLV它的工作。
的我可以只使用LS但我的文件夹中的其他文件类型。的

  LS |排序--version排序-f |尾-n 20
e680.flv
e681.flv
e682.flv
e683.flv
e684.flv
e685.flv
e686.flv
e687.flv
e688.flv
e689.flv
e690.flv
e691.flv
e692.flv
e693.flv
e694.flv
e695.flv
e696.flv
 

我试过到目前为止：

  LS |排序--version排序-f | grep的FLV
    LS *。FLV |排序--version排序-f
    。LS * \\ FLV |排序--version排序-f
    LS *。FLV |排序-f
 

解决方案

我会尝试以下code。作品在我的测试场景：

  LS -1 * \\ FLV。|排序-n -k1.2
 

的 LS 列出每行flv文件1，排序负责在每个第一个（也是唯一一个）字行第二个字符开始（数量开始）。排序数字

I need to sort .flv files numerically and i was able to do it with the following command:

ls *\.flv | sort --version-sort -f

but with many files(hundreds) it's not sorting correctly.

ls *\.flv | sort --version-sort -f | tail -n 20
e680.flv
e681.flv
e682.flv
e683.flv
e684.flv
e685.flv
e686.flv
e687.flv
e688.flv
e689.flv
e690.flv
e691.flv
e692.flv
e693.flv
e694.flv
e695.flv
**e696.flv**
s572.flv
s602.flv
s654.flv

but the strange this is, if i'm ruining the command without "*.flv" it's working. i could use just ls but i have other file types in the folder.

ls | sort --version-sort -f | tail -n 20
e680.flv
e681.flv
e682.flv
e683.flv
e684.flv
e685.flv
e686.flv
e687.flv
e688.flv
e689.flv
e690.flv
e691.flv
e692.flv
e693.flv
e694.flv
e695.flv
e696.flv

what i've tried so far:

    ls | sort --version-sort -f | grep "flv"
    ls *.flv | sort --version-sort -f
    ls *\.flv | sort --version-sort -f
    ls *.flv | sort -f

解决方案

I would try following code. Works on my testing scenario:

ls -1 *\.flv | sort -n -k1.2

The ls lists flv files 1 on each line, sort takes first (and only one) word on each line starting on second character (start of the number). Sorts numerically

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