在java中为高分数排序数字 [英] Sorting numbers for highscores in java

问题描述

我的游戏有一个高分系统。我希望能够按照自动排序对数字进行排序，我有办法对数字进行排序

Ive got a highscore system for my game. and i want to be able to sort the numbers in acending order,ive got a way to sort the numbers

   public static int[] sort(int[] a){
    Arrays.sort(a);
    return a;
}

但我怎么做才能让分数与玩家的名字保持一致那套呢？
例如
me：10
你：50

but how do i make it so the scores stay with the name of the player that set it? for example me:10 you:50

你应该是1号而我应该是nubmer 2.怎么样我使它在排序时使字符串与int保持一致？谢谢

You should be number 1 and me should be nubmer 2. how to i make it so that the string stays with the int when its sorted? thanks

推荐答案

最简单的方法是创建一个类来保存此人的姓名和分数。让它实现Comparable接口，在 compareTo（...）方法中比较当前对象的分数， this ，传递给方法的对象，然后就像你正在做的那样对这个类的对象数组进行排序。

Easiest is to create a class to hold the person's name and score. Make it implement the Comparable interface, in the compareTo(...) method compare the score of the current object, this, to the object being passed into the method, and then sort an array of objects of this class just as you're doing.

class MyFoo implements Comparable<MyFoo> {
  private String name;
  private int score;

  public MyFoo(String name, int score) {
     // ... etc...
  }

  // getter methods here

  public int compareTo(MyFoo other) {
    return score - other.getScore();
  }

  //.... etc...
}

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