如何转换data.table的多个列和值? [英] How to cast multiple columns and values of a data.table?

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本文介绍了如何转换data.table的多个列和值?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我的数据结构如下:

  DT < -  data.table(Id = c(1,1, 1,10,100,100,101,101,101),
Date = as.Date(c(1997-01-01,1997-01-02,1997-01- 03,1997-01-04,
1997-01-02,1997-01-02,1997-01-04,1997-01-03,
1997-01-04,1997-01-04)),
group = c(1,1,1,1,1,2,2,2,2,2),
Price.1 = c(29,25,14,26,30,16,13,62,12,6),
Price.2 = c(4,5,6,6,8,2 ,3,5,7,8))

> DT
Id日期组价格1价格2
1:1 1997-01-01 1 29 4
2:1 1997-01-02 1 25 5
3:1 1997-01-03 1 14 6
4:1 1997-01-04 1 26 6
5: 10 1997-01-02 1 30 8
6:100 1997-01-02 2 16 2
7:100 1997-01-04 2 13 3
8:101 1997-01- 03 2 62 5
9:101 1997-01-04 2 12 7
10:101 1997-01-04 2 6 8

我试图投射它(使用dcast.data.table):

  dcast.data.table(DT,Id〜Date,fun = sum,value.var =Price.1)
dcast.data.table(DT,Id〜group,fun = sum,value。 var =Price.1)
dcast.data.table(DT,Id〜Date,fun = sum,value.var =Price.2)
dcast.data.table Id〜group,fun = sum,value.var =Price.2)

4个单独的输出我试图得到以下:

  Id 1997-01-01 1997-01-02 1997-01- 03 1997-01-04 1 2价格
1:1 29 25 14 26 94 0价格1
2:10 0 30 0 0 30 0价格1
3:100 0 16 0 13 0 29价格1
4:101 0 0 62 18 0 80价格1
5:1 4 5 6 6 21 0价格2
6:10 0 8 0 0 8 0价格2
7:100 0 2 0 3 0 5价格2
8:101 0 0 5 15 0 20价格2
pre>

我的工作环境使用rbind,cbind和合并。

  cbind(rbind(merge(dcast.data.table(DT,Id〜Date,fun = sum,value.var =Price.1),
dcast.data.table(DT,Id〜 group,fun = sum,value.var =Price.1)by byId,all.x = T),
merge(dcast.data.table(DT,Id〜Date,fun = sum,value.var =Price.2),
dcast.data.table(DT,Id_group,fun = sum,value.var =Price.2),by =Id all.x = T)),
Price = c(Price.1,Price.1,Price.1,Price.1,Price.2,Price.2 ,Price.2,Price.2))

我假设每个 Id 映射到一个独特的,并摆脱该变量,但在其他方面本质上与@ user227710的答案相同。

  Idg < -  unique(DT [,。(Id,group)])
DT [,group:= NULL]

res ; -dcast(
melt(DT,id.vars = c(Id,Date)),
variable + Id〜Date,
value.var =
fill = 0,
marginins =Date,
fun.aggregate = sum


#如果你想让群组回来... 。
setDT(res)#在data.table 1.9.5之前需要,其中使用dcast.data.table是另一个选项
setkey(res,Id)
res [Idg] [order变量,Id)]

它提供

 变量Id 1997-01-01 1997-01-02 1997-01-03 1997-01-04(all)group 
1:Price.1 1 29 25 14 26 94 1
2:Price.2 1 4 5 6 6 21 1
3:Price.1 10 0 30 0 0 30 1
4:Price.2 10 0 8 0 0 8 1
5:Price.1 100 0 16 0 13 29 2
6:Price.2 100 0 2 0 3 5 2
7:Price.1 101 0 0 62 18 80 2
8:Price.2 101 0 0 5 15 20 2


my data is structured as follows:

DT <- data.table(Id = c(1, 1, 1, 1, 10, 100, 100, 101, 101, 101), 
                 Date = as.Date(c("1997-01-01", "1997-01-02", "1997-01-03", "1997-01-04", 
                                  "1997-01-02", "1997-01-02", "1997-01-04", "1997-01-03", 
                                  "1997-01-04", "1997-01-04")),
                 group = c(1,1,1,1,1,2,2,2,2,2),
                 Price.1 = c(29, 25, 14, 26, 30, 16, 13, 62, 12,  6), 
                 Price.2 = c(4, 5, 6, 6, 8, 2, 3, 5, 7, 8))

>DT
     Id       Date group Price.1 Price.2
 1:   1 1997-01-01     1      29       4
 2:   1 1997-01-02     1      25       5
 3:   1 1997-01-03     1      14       6
 4:   1 1997-01-04     1      26       6
 5:  10 1997-01-02     1      30       8
 6: 100 1997-01-02     2      16       2
 7: 100 1997-01-04     2      13       3
 8: 101 1997-01-03     2      62       5
 9: 101 1997-01-04     2      12       7
10: 101 1997-01-04     2       6       8

I am trying to cast it (using dcast.data.table):

dcast.data.table(DT, Id ~ Date, fun = sum, value.var = "Price.1") 
dcast.data.table(DT, Id ~ group, fun = sum, value.var = "Price.1")
dcast.data.table(DT, Id ~ Date, fun = sum, value.var = "Price.2")
dcast.data.table(DT, Id ~ group, fun = sum, value.var = "Price.2")

but rather than 4 separate outputs I am trying to get the following:

    Id 1997-01-01 1997-01-02 1997-01-03 1997-01-04  1  2   Price
1:   1         29         25         14         26 94  0 Price.1
2:  10          0         30          0          0 30  0 Price.1
3: 100          0         16          0         13  0 29 Price.1
4: 101          0          0         62         18  0 80 Price.1
5:   1          4          5          6          6 21  0 Price.2
6:  10          0          8          0          0  8  0 Price.2
7: 100          0          2          0          3  0  5 Price.2
8: 101          0          0          5         15  0 20 Price.2

and my work-around uses rbind, cbind, and merge.

cbind(rbind(merge(dcast.data.table(DT, Id ~ Date, fun = sum, value.var = "Price.1"), 
            dcast.data.table(DT, Id ~ group, fun = sum, value.var = "Price.1"), by = "Id", all.x  = T),
      merge(dcast.data.table(DT, Id ~ Date, fun = sum, value.var = "Price.2"),
            dcast.data.table(DT, Id ~ group, fun = sum, value.var = "Price.2"), by = "Id", all.x  = T)),
      Price = c("Price.1","Price.1","Price.1","Price.1","Price.2","Price.2","Price.2","Price.2"))

Is there an existing and cleaner way to do this?

解决方案

I make the assumption that each Id maps to a unique group and get rid of that variable, but otherwise this is essentially the same as @user227710's answer.

Idg <- unique(DT[,.(Id,group)])
DT[,group:=NULL]

res <- dcast(
  melt(DT, id.vars = c("Id","Date")),
  variable+Id ~ Date,
  value.var = "value",
  fill = 0,
  margins = "Date",
  fun.aggregate = sum
)

# and if you want the group back...
setDT(res) # needed before data.table 1.9.5, where using dcast.data.table is another option
setkey(res,Id)
res[Idg][order(variable,Id)]

which gives

   variable  Id 1997-01-01 1997-01-02 1997-01-03 1997-01-04 (all) group
1:  Price.1   1         29         25         14         26    94     1
2:  Price.2   1          4          5          6          6    21     1
3:  Price.1  10          0         30          0          0    30     1
4:  Price.2  10          0          8          0          0     8     1
5:  Price.1 100          0         16          0         13    29     2
6:  Price.2 100          0          2          0          3     5     2
7:  Price.1 101          0          0         62         18    80     2
8:  Price.2 101          0          0          5         15    20     2

这篇关于如何转换data.table的多个列和值?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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