这个int在C中的float转换有什么问题吗? [英] What is wrong with this int to float conversion in C?
问题描述
float a = 1.32;
int * b;
b =& a;
printf(%d,* b);
这段代码把float变成了一个int,但是我得到的输出是:1068037571
这与计算机的IEEE 754转换功能有关吗?
Thanks!
您的程序调用未定义的行为。您只是将 float
的表示方式重新解释为 int
。您绝对不会将 int
转换为 float
。你不能指望任何特定的行为。
要将float转换为int,您可以使用如下代码:
int b = a;
将 float
截断为 int
。
I'm confused by the output of the following bit of code:
float a = 1.32;
int* b;
b= &a;
printf("%d", *b);
This bit of code turns the float into an int, but the output I'm getting is: 1068037571
Is this related to the IEEE 754 converting capabilities of the computer? Thanks!
Your program invokes undefined behaviour. You are simply reinterpreting the representation of the float
as an int
. You are categorically not converting an int
to a float
. You cannot expect any particular behaviour.
To convert the float into an int you would use code like this:
int b = a;
which truncates the float
to an int
.
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