如何提取非支配解(帕累托前沿) [英] How to extract the non-dominated solutions (Pareto front)

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问题描述

我曾多次尝试使用MATLAB为两个目标函数编写提取非主导(或主导)的

解的代码。



我有两个简单的目标函数:

J1 = x。^ 2

J2 =(x-2)。^ 2



我有一个x值的范围,比如-5到5,例如,100个解决方案是在指定范围内随机生成的



我想提取非支配来自这些解决方案的解决方案。



我没有任何上述操作的问题。我到目前为止所做的是:

 %在-5和5之间随机生成100个解决方案:

X = -5 + 10 *兰特(100,1);

%计算两个目标函数,每个解决方案的J1和J2:

J1 = x。^ 2;

J2 =(x-2)。^ 2;

现在,我面临如何将概念转化为书面代码的问题。



我知道如何提取非支配解和Pareto前沿的概念。

我可以手动完成,但是这个需要很长时间。



我尝试使用if语句,但结果不准确。



我认为最好提取主导解的指数,然后将它们从主矢量x中移除以获得非主导解。$ b $

预先感谢

解决方案

你介意来自FEX的文件吗? 这个作品完美无缺:由Yi Cao创作的Pareto Front p>

为您提供了主导解决方案的 x 指数。

然后你只需要像这样使用它:

  x = -5 + 10 * rand(100,1); 
J1 = x。^ 2;
J2 =(x-2)。^ 2;

idx = paretofront([J1,J2]);
xdi =〜ismember(idx,1:numel(x));

图(1)
持有
分散(J1,J2,10,'red');
scatter(J1(idx),J2(idx),50,'blue');
scatter(J1(xdi),J2(xdi),50,'green');
延期

legend('all solutions','dominating solutions','non dominating solutions')

导致:


这正是它应该看起来的样子。否则,您需要澄清您的问题。


I have tried so many times to write the code of extracting the non-dominated (or dominated)

solutions for two objective functions using MATLAB.

I have two simple objective functions:

J1=x.^2

J2=(x-2).^2

and I have a range for x values, say from -5 to 5 and there are, for example, 100 solutions to be

generated randomly within the range specified.

I want to extract the non-dominated solutions from these solutions.

I have no problem of all above operations. What I have done so far is:

   % generating 100 solutions randomly between -5 and 5:

   x=-5+10*rand(100,1);

   % calculate both objective functions, J1 and J2 at each solution:

   J1=x.^2;

   J2=(x-2).^2;

Now, I faced the problem of how to translate the concept to a written code.

I know the concept of how to extract the non-dominated solutions and Pareto front.

I can do it manually but this will take very long time.

I tried using if statements but the results were not accurate.

I think it is better to extract the indices of the dominated solutions and then remove them from

the main vector x to get the non-dominated solutions.

Thanks in advance

解决方案

do you mind files from FEX? This one works perfectly: "Pareto Front" by Yi Cao

giving you the indices of x of dominating solutions.

Then you just have to use it like this:

x=-5+10*rand(100,1);
J1=x.^2;
J2=(x-2).^2;

idx = paretofront([J1,J2]);
xdi = ~ismember(idx,1:numel(x));

figure(1)
hold on
scatter(J1,J2,10,'red');
scatter(J1(idx),J2(idx),50,'blue');
scatter(J1(xdi),J2(xdi),50,'green');
hold off

legend('all solutions','dominating solutions','non dominating solutions')

leads to:

which is exactly how it is supposed to look like. Otherwise you need to clarify your question.

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