HTTPResponse为Java中的JSON [英] HTTPResponse as JSON in Java

问题描述

我试图从HTTP响应中获取JSONObject。

I was trying to get an JSONObject from a HTTP response.

try
    {   
        GetMethod postMethod = new GetMethod();
        postMethod.setURI(new URI(url, true));
        postMethod.setRequestHeader("Accept", "application/json");
        httpClient.executeMethod(postMethod);
        String resp=postMethod.getResponseBodyAsString();
        org.json.JSONTokener tokener = new org.json.JSONTokener(resp);
        finalResult = new org.json.JSONArray(tokener);

        return finalResult;
    }

但我得到了运行时警告

转到大型或未知大小的缓冲响应体。建议使用 getResponseBodyAsStream 。

我应该以流的形式获得响应JVM建议？如果是这样，我怎么能解析它的JSON？

Should I get the response as stream as suggested by the JVM ? If so, how could I parse the JSON from it ?

推荐答案

如果你想从服务器发送 jsonObjects （tomcat服务器） ）

if you want to send jsonObjects from server suppose (tomcat server)

对于服务器端 -

创建 jsonobjects -

我已经调用 toJson（）来创建 jsonobjects 这是实现 -

I have Called toJson() for creating jsonobjects this is the implementation-

final JSONObject arr = new JSONObject();

for (int i = 0; i < contactStatus.size(); i++) {
    ContactStatus contactObject = contactStatus.get(i);

    try {
        arr.put(String.valueOf(i), toJson(value1, value2,, value3));
    } catch (JSONException e) {

     catch block e.printStackTrace();
    }
}

//Here we serialize the stream to a String.
final String output = arr.toString();
response.setContentLength(output.length());
out.print(output);//out is object of servlet output stream.

public static Object toJsonForContact(String value1, boolean value2, double value3) throws JSONException {

    JSONObject contactObject = new JSONObject();
    contactObject.put("id", id);
    contactObject.put("status", value1);
    contactObject.put("distance", value2);
    contactObject.put("relation", value3);
    return contactObject;
}

所以你的 jsonobjects 已准备好发送我们将这些对象写入 ServletoutputStream 。

so your jsonobjects are ready for sending we write these objects to ServletoutputStream.

在客户端 -

while ((ReadResponses = in.readLine()) != null) {
        Constants.Response_From_server = ReadResponses;

        if (Constants.Response_From_server.startsWith("{")) {
            ListOfContactStatus = new ArrayList<ContactStatus>();
            ContactStatus contactStatusObject;

            try {
                JSONObject json = new JSONObject(Constants.Response_From_server);

                for (int i = 0; i < json.length(); i++) {
                    contactStatusObject = new ContactStatus();

                    JSONObject json1 = json.getJSONObject(String.valueOf(i));
                    System.out.println("" + json1.getString("id"));
                    System.out.println("" + json1.getBoolean("status"));
                    System.out.println("" + json1.getDouble("distance"));

                    contactStatusObject.setId(json1.getString("id"));
                    contactStatusObject.setStatus(json1.getBoolean("status"));
                    contactStatusObject.setDistance((float) json1.getDouble("distance"));
                    ListOfContactStatus.add(contactStatusObject);
                    System.out.println("HTTPTransport:sendMessage  Size of ListOfContactStatus" + ListOfContactStatus.size());
                }
            } catch (JSONException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
        }
    }
}

这篇关于HTTPResponse为Java中的JSON的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！