如何在JavaScript中通过其属性获取对象的索引？ [英] How to get index of object by its property in JavaScript?

问题描述

例如我有：

var Data = [
  { id_list: 1, name: 'Nick', token: '312312' },
  { id_list: 2, name: 'John', token: '123123' },
]

然后我想通过 name 排序/反向此对象。我得到这样的东西：

Then i want to sort/reverse this object by name, for example. I get something like this:

var Data = [
  { id_list: 2, name: 'John', token: '123123' },
  { id_list: 1, name: 'Nick', token: '312312' },
]

现在我想知道具有属性 name ='John'的对象索引，以获取属性令牌的值。

And now i want to know index of object with property name='John' to get value of property token.

推荐答案

正如其他答案所示，循环遍历数组可能是最好的方法。但我会把它放在它自己的函数中，并使它更抽象一点：

As the other answers suggest, looping through the array is probably the best way. But I would put it in it's own function, and make it a little more abstract:

function findWithAttr(array, attr, value) {
    for(var i = 0; i < array.length; i += 1) {
        if(array[i][attr] === value) {
            return i;
        }
    }
    return -1;
}

var Data = [
    {id_list: 2, name: 'John', token: '123123'},
    {id_list: 1, name: 'Nick', token: '312312'}
];

有了这个，您不仅可以找到哪个包含'John'，而且您可以找到包含token'312312'：

With this, not only can you find which one contains 'John' but you can find which contains the token '312312':

findWithAttr(Data, 'name', 'John'); // returns 0
findWithAttr(Data, 'token', '312312'); // returns 1
findWithAttr(Data, 'id_list', '10'); // returns -1

编辑：
更新后的功能未找到时返回-1，因此它遵循与相同的结构Array.prototype.indexOf（）

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