如何在JavaScript或jQuery中过滤JSON数据？ [英] How to filter JSON Data in JavaScript or jQuery?

问题描述

如何使用Javascript或jQuery过滤JSON数据？

How to filter JSON data using Javascript or jQuery?

这是我的JSON数据：

This my JSON data:

[{"name":"Lenovo Thinkpad 41A4298","website":"google"},
{"name":"Lenovo Thinkpad 41A2222","website":"google"},
{"name":"Lenovo Thinkpad 41Awww33","website":"yahoo"},
{"name":"Lenovo Thinkpad 41A424448","website":"google"},
{"name":"Lenovo Thinkpad 41A429rr8","website":"ebay"},
{"name":"Lenovo Thinkpad 41A429ff8","website":"ebay"},
{"name":"Lenovo Thinkpad 41A429ss8","website":"rediff"},
{"name":"Lenovo Thinkpad 41A429sg8","website":"yahoo"}]

JavaScript：

JavaScript:

obj1 = JSON.parse(jsondata);

现在我只想要包含网站的名称和网站数据等于yahoo

now I only want name and website data which is contain website is equal to "yahoo"

推荐答案

这就是你应该这样做的方法:(谷歌查找）

This is how you should do it : ( for google find)

$([
  {"name":"Lenovo Thinkpad 41A4298","website":"google222"},
  {"name":"Lenovo Thinkpad 41A2222","website":"google"}
  ])
    .filter(function (i,n){
        return n.website==='google';
    });

更好解决方案:( Salman's）

Better solution : ( Salman's)

$.grep( [{"name":"Lenovo Thinkpad 41A4298","website":"google"},{"name":"Lenovo Thinkpad 41A2222","website":"google"}], function( n, i ) {
  return n.website==='google';
});

http://jsbin.com/yakubixi/4/edit

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