如何从location.search获取特定参数？ [英] How can I get a specific parameter from location.search?

问题描述

如果我有一个URL，例如

If I had a URL such as

http://localhost/search.php?year=2008

我如何编写JavaScript函数来获取变量 year 并查看它是否包含什么？

How would I write a JavaScript function to grab the variable year and see if it contains anything?

我知道可以用 location.search 完成但我无法弄清楚它是如何抓住的参数。

I know it can be done with location.search but I can’t figure out how it grabs parameters.

推荐答案

我最喜欢获取URL参数的方法是这种方法：

My favorite way for getting URL params is this approach:

var parseQueryString = function() {

    var str = window.location.search;
    var objURL = {};

    str.replace(
        new RegExp( "([^?=&]+)(=([^&]*))?", "g" ),
        function( $0, $1, $2, $3 ){
            objURL[ $1 ] = $3;
        }
    );
    return objURL;
};

//Example how to use it: 
var params = parseQueryString();
alert(params["foo"]); 

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