如何发出jsonp请求 [英] How to make a jsonp request

问题描述

我需要做一些跨站点脚本。下面的代码块包含jsonp的方法，该方法返回就好像失败了，但当我将其更改为get请求时，我就获得了成功。我需要能够使用jsonp方法成功响应。可以排除以下内容。响应是有效的json，这个param在url？callback = JSON_CALLBACK中。这是我通过执行http请求获得的json和执行此代码的代码块。

I need to do some cross site scripting. The block of code below contains the method of jsonp, the method returns as if it failed, but when I change it to be a get request I then have success. I need to be able to a successful response using the jsonp method. The following can be ruled out. The response is valid json and this param is in the url ?callback=JSON_CALLBACK. Here is the json I receive from doing the http request and the code block that executes this code.

http响应状态代码200

http response status code 200

[{"cube":"1" ,"points":"160"},{"cube":"2","points":"690"},{"cube":"3","points":"331"}]

代码块

 var myApp = angular.module('test', []);

    myApp.controller('UserCtrl', function($scope, users) {
        $scope.usersPerCube = users.getUsers();
    })

    myApp.factory('users', function($http) {
       return {
         getUsers: function() {
           var deferred = $q.defer();
           var url = "http://localhost/api/api/index.php/analytics/UsersPerCube?callback=JSON_CALLBACK";
         $http.get(url).success(function (data, status, headers, config) {
                console.log(data);
                deferred.resolve(data);
            }).error(function (data, status, headers, config) {
                //this always gets called
                console.log(status);
                deferred.reject(status);
            });
            return deferred.promise;

     }
   }

请注意，我已编辑了服务器端代码，现在已收到

Note that I have edited my server side code and now receive

"angular.callbacks._1( {"cube":"1","points":"160"},{"cube":"2","points":"690"},{"cube":"3","points":"331"})"

UPDATE
以上内容有效，现在正在执行成功方法。我只需要弄清楚如何解析对象。一旦我找到答案，我会再次发帖。

UPDATE The above is valid and now the success method is executing. I just need to figure out how to parse the objects. I will post again once I figure out the answer.

推荐答案

我决定详细说明如何做一个< a href =http://en.wikipedia.org/wiki/JSONP =nofollow noreferrer> jsonp 请求，以便其他人不会遇到与我相同的麻烦。

I have decided to give a detailed description of how to do a jsonp request so others will not run into the same troubles as I did.

myApp.factory('users', function($http) {
       return {
         getUsers: function() {
           var deferred = $q.defer();
           var url = "http://localhost/api/api/index.php/analytics/UsersPerCube?callback=JSON_CALLBACK";
         $http.get(url).success(function (data, status, headers, config) {
                console.log(data);
                deferred.resolve(data);
            }).error(function (data, status, headers, config) {
                //this always gets called
                console.log(status);
                deferred.reject(status);
            });
            return deferred.promise;

     }  

<请注意，网址包含？callback = JSON_CALLBACK 。这是一个很好的stackoverflow。一旦你得到了然后你会得到一个像下面那样的json。

Notice that the url contains ?callback=JSON_CALLBACK. Here is a nice stackoverflow on that. Once you get the response then you'll receive a json like the one below.

"angular.callbacks._1( {"cube":"1","points":"160"},{"cube":"2","points":"690"},{"cube":"3","points":"331"})"

这是一个关于该主题的很好的stackoverflow

现在我得到的一个部分是服务器必须返回 GET param，回调。这是一个很好的教程。 http://niryariv.wordpress.com/2009/05/05/jsonp -quickly / 所以json看起来像上面那个。

Now the one part that got me is that the server has to return the GET param, callback. Here is a good tutorial for that. http://niryariv.wordpress.com/2009/05/05/jsonp-quickly/ So the json looks like the one above.

嗯，我希望将来可以帮到某人。

Well, I hope this helps someone in the future.

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