getElementById（）通配符 [英] getElementById() wildcard

问题描述

我有一个div，并且我有一些未定义级别的子节点。

I got a div, and there i got some childnodes in undefined levels.

现在我必须将每个元素的ID更改为一个div。如何实现？

Now I have to change the ID of every element into one div. How to realize?

我想，因为他们有上传ID，所以如果父亲是id ='path_test_maindiv'那么下一个下行者将是'path_test_maindiv_child'，因此我想，我会通过通配符解决这个问题，例如：

I thought, because they have upgoing IDs, so if the parent is id='path_test_maindiv' then the next downer would be 'path_test_maindiv_child', and therefore I thought, I'd solve that by wildcards, for example:

document.getElementById('path_test_*')

这可能吗？或者还有其他方法吗？

Is this possible? Or are there any other ways?

推荐答案

不在本机JavaScript中。你有各种选择：

Not in native JavaScript. You have various options:

1）放一个类并使用getElementsByClassName但是它不适用于每个浏览器。

1) Put a class and use getElementsByClassName but it doesn't work in every browser.

2）制作自己的功能。类似于：

2) Make your own function. Something like:

function getElementsStartsWithId( id ) {
  var children = document.body.getElementsByTagName('*');
  var elements = [], child;
  for (var i = 0, length = children.length; i < length; i++) {
    child = children[i];
    if (child.id.substr(0, id.length) == id)
      elements.push(child);
  }
  return elements;
}

3）使用库或CSS选择器。像jQuery;）

3) Use a library or a CSS selector. Like jQuery ;)

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