如何检查脚本是否在node.js下运行？ [英] How to check whether a script is running under node.js?

问题描述

我需要一个node.js脚本的脚本，我想让javascript引擎保持独立。

I have a script I am requiring from a node.js script, which I want to keep javascript engine independent.

所以，例如，我想做：

exports.x = y;

我该如何执行此测试？

编辑：发布此问题时，我不知道node.js模块功能是基于 commonjs 。

When posting this question, I didn't know the node.js modules feature is based on commonjs.

对于具体示例，我给了一个更准确的问题是：

For the specific example I gave a more accurate question would've been:

脚本如何判断是否需要将其作为commonjs模块？

How can a script tell whether it has been required as a commonjs module?

推荐答案

通过寻找CommonJS支持，这就是 Underscore.js 库就可以了：

By looking for CommonJS support, this is how the Underscore.js library does it:

编辑：更新的问题：

(function () {

    // Establish the root object, `window` in the browser, or `global` on the server.
    var root = this; 

    // Create a reference to this
    var _ = new Object();

    var isNode = false;

    // Export the Underscore object for **CommonJS**, with backwards-compatibility
    // for the old `require()` API. If we're not in CommonJS, add `_` to the
    // global object.
    if (typeof module !== 'undefined' && module.exports) {
            module.exports = _;
            root._ = _;
            isNode = true;
    } else {
            root._ = _;
    }
})();

这里的例子保留了模块模式。

Example here retains the Module pattern.

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