为什么(“foo”=== new String(" foo"))在JavaScript中评估为false? [英] Why does ("foo" === new String("foo")) evaluate to false in JavaScript?
问题描述
在比较字符串值时,我会一直开始使用===(三等号,严格比较),但现在我发现
I was going to start using === (triple equals, strict comparison) all the time when comparing string values, but now I find that
"foo" === new String("foo")
为false ,与此相同:
is false, and same with this:
var f = "foo", g = new String("foo");
f === g; // false
当然:
f == g; // true
因此建议始终使用==进行字符串比较,或者始终将变量转换为比较前的字符串?
So is it recommended to always use == for string comparison, or always convert variables to strings before comparing?
推荐答案
foo
是一个字符串原始。 (这个概念在C#或Java中不存在)
"foo"
is a string primitive. (this concept does not exist in C# or Java)
new String(foo)
是盒装字符串对象。
===
运算符在基元和对象上表现不同。
比较基元(相同类型)时, ===如果
都具有相同的值,则返回true。
The ===
operator behaves differently on primitives and objects.
When comparing primitives (of the same type), ===
will return true if they both have the same value.
比较对象时, ===
只有在引用同一个对象时才会返回true(通过引用进行比较)。因此, new String(a)!== new String(a)
。
When comparing objects, ===
will return true only if they refer to the same object (comparing by reference). Thus, new String("a") !== new String("a")
.
在你的case, ===
返回false,因为操作数的类型不同(一个是基元,另一个是对象)。
In your case, ===
returns false because the operands are of different types (one is a primitive and the other is an object).
原语根本不是对象。
typeof
运算符不会返回对象
用于基元。
Primitives are not objects at all.
The typeof
operator will not return "object"
for primitives.
当您尝试访问基元的属性(将其用作对象)时,Javascript语言将它封装到一个对象,每次都创建一个新对象。 规范中对此进行了描述。
When you try to access a property of a primitive (using it as an object), the Javascript language will box it to an object, creating a new object every time. This is described in the specification.
这就是你不能在基元上放置属性的原因:
This is why you cannot put properties on primitives:
var x = "a";
x.property = 2;
alert(x.property) //undefined
每次写 x.property
,创建一个不同的盒装 String
对象。
Each time you write x.property
, a different boxed String
object is created.
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