如何为Firebase构建云功能以从多个文件部署多个功能？ [英] How do I structure Cloud Functions for Firebase to deploy multiple functions from multiple files?

问题描述

我想为Firebase创建多个云功能，并从一个项目同时部署它们。我还想将每个函数分成一个单独的文件。目前我可以创建多个函数，如果我将它们都放在index.js中，例如：

I would like to create multiple Cloud Functions for Firebase and deploy them all at the same time from one project. I would also like to separate each function into a separate file. Currently I can create multiple functions if I put them both in index.js such as:

exports.foo = functions.database.ref('/foo').onWrite(event => {
    ...
});

exports.bar = functions.database.ref('/bar').onWrite(event => {
    ...
});

但是我想将foo和bar放在单独的文件中。我试过这个：

However I would like to put foo and bar in separate files. I tried this:

/functions
|--index.js (blank)
|--foo.js
|--bar.js
|--package.json

其中foo.js是

exports.foo = functions.database.ref('/foo').onWrite(event => {
    ...
});

和bar.js是

exports.bar = functions.database.ref('/bar').onWrite(event => {
    ...
});

有没有办法在不将所有函数放入index.js的情况下完成此操作？

Is there a way to accomplish this without putting all functions in index.js?

推荐答案

啊，Firebase的云端功能正常加载节点模块，所以这个工作

Ah, Cloud Functions for Firebase load node modules normally, so this works

结构：

/functions
|--index.js
|--foo.js
|--bar.js
|--package.json

index.js：

index.js:

const functions = require('firebase-functions');
const fooModule = require('./foo');
const barModule = require('./bar');

exports.foo = functions.database.ref('/foo').onWrite(fooModule.handler);
exports.bar = functions.database.ref('/bar').onWrite(barModule.handler);

foo.js：

exports.handler = (event) => {
    ...
};

bar.js：

exports.handler = (event) => {
    ...
};

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