在特定时间打开承诺的承诺金额 [英] Throttle amount of promises open at a given time

问题描述

以下Typescript每次执行一次对 doSomething（action）的每次调用。 （意思是列表中的第二项在第一项完成之前不会进行调用）。

The following Typescript performs each call to doSomething(action) one at a time. (Meaning the second item in the list does not get a call made until the first one is done).

async performActionsOneAtATime() {
    for (let action of listOfActions) {
        const actionResult = await doSomethingOnServer(action);
        console.log(`Action Done: ${actionResult}`);
    }
 }

这个会将所有请求发送到服务器权利离开（不等待任何回复）：

This one will send all the requests to the server right away (without waiting for any responses):

async performActionsInParallel() {
    for (let action of listOfActions) {
        const actionResultPromise = doSomething(action);
        actionResultPromise.then((actionResult) => {
            console.log(`Action Done: ${actionResult}`);
        });
    }
}

但我真正需要的是一种方法来扼杀他们。也许一次打开10或20个电话。 （一次一个太慢，但所有600都会使服务器超载。）

But what I really need is a way to throttle them. Maybe have 10 or 20 calls open at a time. (One at at a time is too slow, but all 600 will overload the server.)

但我很难搞清楚这一点。

But I am having a hard time figuring this out.

有关如何限制每次打开X的来电数量的任何建议吗？

（这个问题使用TypeScript，但我对ES6 JavaScript答案没问题。）

(This question uses TypeScript, but I would be fine with an ES6 JavaScript answer.)

推荐答案

你可以在一个简短的功能中执行此操作（更新：按照naomik的建议按顺序返回值。）

You can do this in one short function. (Update: Returns values in order per naomik's suggestion.)

/**
 * Performs a list of callable actions (promise factories) so that only a limited
 * number of promises are pending at any given time.
 *
 * @param listOfCallableActions An array of callable functions, which should
 *     return promises.
 * @param limit The maximum number of promises to have pending at once.
 * @returns A Promise that resolves to the full list of values when everything is done.
 */
function throttleActions(listOfCallableActions, limit) {
  // We'll need to store which is the next promise in the list.
  let i = 0;
  let resultArray = new Array(listOfCallableActions.length);

  // Now define what happens when any of the actions completes. Javascript is
  // (mostly) single-threaded, so only one completion handler will call at a
  // given time. Because we return doNextAction, the Promise chain continues as
  // long as there's an action left in the list.
  function doNextAction() {
    if (i < listOfCallableActions.length) {
      // Save the current value of i, so we can put the result in the right place
      let actionIndex = i++;
      let nextAction = listOfCallableActions[actionIndex];
      return Promise.resolve(nextAction())
          .then(result => {  // Save results to the correct array index.
             resultArray[actionIndex] = result;
             return;
          }).then(doNextAction);
    }
  }

  // Now start up the original <limit> number of promises.
  // i advances in calls to doNextAction.
  let listOfPromises = [];
  while (i < limit && i < listOfCallableActions.length) {
    listOfPromises.push(doNextAction());
  }
  return Promise.all(listOfPromises).then(() => resultArray);
}

// Test harness:

function delay(name, ms) {
  return new Promise((resolve, reject) => setTimeout(function() {
    console.log(name);
    resolve(name);
  }, ms));
}

var ps = [];
for (let i = 0; i < 10; i++) {
  ps.push(() => delay("promise " + i, Math.random() * 3000));
}

throttleActions(ps, 3).then(result => console.log(result));

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