正则表达式匹配未跟随另一个特定字符的字符 [英] Regex Match a character which is not followed by another specific character
问题描述
我正在为Brackets编写CodeMirror扩展。要defineSimpleCodeMode,我需要做一些模式匹配,我想弄清楚如何实现$ subject。
I'm writing a CodeMirror extension for Brackets. To defineSimpleCodeMode I need to do some pattern matching and I'm trying to figure out how to achieve $subject.
例如
匹配所有html标签的<
Match <
of all the html tags
<body>
并忽略后跟<%$ c的html标签$ c>
<% if %>
注意:我只想获得起始<
of it
Note: I only want to get the starting <
of it
如果有人可以帮助我,那将是一个很大的帮助。如果您需要更多详细信息,请告诉我。
If some can help me out it would be a great help. Please do let me know if you need anymore details.
谢谢!
推荐答案
虽然这似乎是一个坏主意,但我可以看到两种方法:
While this seems to be a bad idea, I can see two ways of doing it :
(<)(?:[^%])
[^]
sequence允许您搜索除以下字符之外的任何内容。
The [^]
sequence allows you to search for anything but the following character.
(?:)
序列适用于非捕获组。
The (?:)
sequence is for non capturing groups.
<(?!%)
(?!)
序列如果与以下字符不匹配,则成功,但不是捕获。
The (?!)
sequence succeeds if it doesn't match the following character, but is not captured.
(?:[^%])(>)
(小心这里,前瞻不会起作用,因为你需要向后看)
(careful here, the lookahead won't work as you need to go backwards)
(?<!%)>
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