如何根据每个元素的长度对数组进行排序？ [英] How to sort an array based on the length of each element?

问题描述

我有这样一个数组：

arr = []
arr[0] = "ab"
arr[1] = "abcdefgh"
arr[2] = "abcd"

排序后，输出数组应为：

After sorting, the output array should be:

arr[0] = "abcdefgh"
arr[1] = "abcd"
arr[2] = "ab"  

我的意思是，我希望按每个元素长度的降序排列。

I mean, I want in the descending order of the length of each element.

推荐答案

您可以使用 Array.sort 排序数组的方法。将字符串长度视为排序标准的排序函数可以按如下方式使用：

You can use Array.sort method to sort the array. A sorting function that considers the length of string as the sorting criteria can be used as follows:

arr.sort(function(a, b){
  // ASC  -> a.length - b.length
  // DESC -> b.length - a.length
  return b.length - a.length;
});

---

注意：排序 [ a，b，c] 按字符串长度不保证返回 [a，b，c] 。根据规范：

---

Note: sorting ["a", "b", "c"] by length of string is not guaranteed to return ["a", "b", "c"]. According to the specs:

排序不一定稳定（也就是说，比较
等于的元素不一定保持原始顺序。）

The sort is not necessarily stable (that is, elements that compare equal do not necessarily remain in their original order).

如果目标是按长度排序，然后按字典顺序排序，则必须指定其他条件：

If the objective is to sort by length then by dictionary order you must specify additional criteria:

["c", "a", "b"].sort(function(a, b) {
  return a.length - b.length || // sort by length, if equal then
         a.localeCompare(b);    // sort by dictionary order
});

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