正则表达式恰好匹配5位数 [英] regular expression to match exactly 5 digits

问题描述

testing= testing.match(/(\d{5})/g);

我正在读一个完整的html变量。从变量中，想要获取具有正好5位数的模式的所有数字。无需关心此数字之前/之后是否有其他类型的单词。只是想确保抓取的是5位数字。

I'm reading a full html into variable. From the variable, want to grab out all numbers with the pattern of exactly 5 digits. No need to care of whether before/after this digit having other type of words. Just want to make sure whatever that is 5 digit numbers been grabbed out.

但是，当我申请它时，它不仅会拔出5位数字，而是还检索了超过5位数...

However, when I apply it, it not only pull out number with exactly 5 digit, number with more than 5 digits also retrieved...

我曾尝试将 ^ 放在前面并且 $ 落后，但它的结果是null。

I had tried putting ^ in front and $ behind, but it making result come out as null.

推荐答案

我正在阅读一个文本文件，并希望使用下面的正则表达式来提取正好5位数的数字，忽略字母。

I am reading a text file and want to use regex below to pull out numbers with exactly 5 digit, ignoring alphabets.

尝试这...

var str = 'f 34 545 323 12345 54321 123456',
    matches = str.match(/\b\d{5}\b/g);

console.log(matches); // ["12345", "54321"]

jsFiddle 。

字边界 \ b 是你的朋友。

我的正则表达式会得到这样的数字 12345 ，但不，如 a12345 。如果你需要后者，其他答案提供了很好的正则表达式。

My regex will get a number like this 12345, but not like a12345. The other answers provide great regexes if you require the latter.

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