使用原生DOM的最近祖先匹配选择器？ [英] Closest ancestor matching selector using native DOM?

问题描述

是否有人在DOM api中处理 jQuery.closest（）等效内容？

Is anybody working on a jQuery.closest() equivalent in the DOM api?

看似选择器级别2草案添加 matches（）相当于 jQuery.is（），因此本机最接近应该更容易编写。是否已向选择器添加 nearest（）？

Looks like the Selectors Level 2 draft adds matches() equivalent to jQuery.is(), so native closest should be much easier to write. Has adding closest() to Selectors come up?

推荐答案

Element.closest（）

支持

使用Element实现此类功能。 matches（）在性能方面似乎不是最优的，因为看起来match（）会在每次测试父级时调用querySelectorAll（），而只有一次调用就足够了。

Implementing such function with Element.matches() seems not optimal in terms of performance, cause apparently matches() will make a call to querySelectorAll() every time you test a parent, while only one call is sufficient for the job.

这是MDN上最近（）的polyfill。请注意一次调用querySelectorAll（）

Here's a polyfill for closest() on MDN. Note a single call to querySelectorAll()

if (window.Element && !Element.prototype.closest) {
  Element.prototype.closest = 
  function(s) {
      var matches = (this.document || this.ownerDocument).querySelectorAll(s),
          i,
          el = this;
      do {
          i = matches.length;
          while (--i >= 0 && matches.item(i) !== el) {};
      } while ((i < 0) && (el = el.parentElement)); 
      return el;
  };
}

但请记住，像这样实现的函数在单独连接的树上无法正常工作（与document.documentElement root分离）

But bear in mind that function implemented like this will not work properly on unattached tree (detached from document.documentElement root)

//Element.prototype.closestTest = function(s){...as seen above...};

var detachedRoot = document.createElement("footer");
var child = detachedRoot.appendChild(document.createElement("div"));
detachedRoot.parentElement; //null

child.closestTest("footer"); //null

document.documentElement.append(detachedRoot);
child.closestTest("footer"); //<footer>   

虽然在Firefox 51.0.1中实现的nearest（）似乎可以在分离树上正常工作

Though closest() that is implemented in Firefox 51.0.1 seems to work fine with detached tree

document.documentElement.removeChild(detachedRoot);
child.closestTest("footer"); //null
child.closest("footer"); //<footer>

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