如何使用java脚本在字符串中搜索多个文本？ [英] How to search for multiple texts in a string, using java script?

问题描述

我有一个字符串，要搜索的单词数组：

I have a string, an array of words to be searched for:

strng = "I have been working here since last six months"
text = ["since", "till", "until"]
result = "since"

我想搜索数组中的每个单词，在 strng 中，当在strng中找到任何单词时，它必须是分配给结果。怎么做？

我用 .search（）搜索单个单词，但是如何搜索多个单词？请帮助。

我是新手。

I want to search for every word in array, in strng and when any of it is found in the strng, it must be assigned to result. how to do it?
I am using .search() for searching a single word, but how to search for multiple words? please help.
I am a Newbie.

推荐答案

您可以循环使用关键字数组或使用正则表达式。前者很简单，后者更优雅; - ）

You can either loop over your array of keywords or use a regular expression. The former is simple, the latter is more elegant ;-)

你的正则表达式应该是/ since | until | until /，但我不是100现在肯定了。如果你打算使用它们，你应该研究一下正则表达式，这里有一个启动器： http：/ /www.w3schools.com/js/js_obj_regexp.asp

Your regex should be something like "/since|till|until/", but I'm not 100% sure right now. You should research a bit about regexes if you're planning to use them, here's a starter: http://www.w3schools.com/js/js_obj_regexp.asp

编辑：试过它并刷新我的记忆。最简单的解决方案是使用.match（），而不是search（）。然后就可以归结为单线：

Just tried it and refreshed my memory. The simplest solution is using .match(), not search(). It's boils down to a one-liner then:

strng.match(/since|till|until/) // returns ["since"]

使用.match（）为您提供一个包含所有模式的数组，在这种情况下，第一个也是唯一一个匹配是该数组的第一个元素。

Using .match() gives you an array with all occurrences of your pattern, in this case the first and only match is the first element of that array.

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