箭头函数和括号()或{}或({})的使用 [英] Arrow functions and the use of parentheses () or {} or ({})

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本文介绍了箭头函数和括号()或{}或({})的使用的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我无法理解为什么在箭头函数中我们不需要在({})大括号中包含箭头函数的文字,而不是在这个例子中,文字只包含在单个()大括号中。为什么?我曾在网上冲浪找到答案,但失败了。

I cannot understand why in the arrow functions we do not need to wrap the literal of arrow function in the ({}) braces, instead of in this example the literal just wrapped in the single () braces. Why? I had surfed the internet to find an answer on it, but it failed.

还有为什么我们把参数放在双括号({})中,而不仅仅是()

And also why we put the arguments in double braces ({}), instead of just ()?

const FilterLink = ({ filter, children }) => (
   <NavLink
       to={filter === 'SHOW_ALL' ? '/' : `/${ filter }`}
       activeStyle={ {
       textDecoration: 'none',
           color: 'black'
       }}
   >
       {children}
   </NavLink>
)


推荐答案

使用({}) destructure 参数和 => ()是一个隐含的返回值,相当于 => {return()} 仅用于消除对象的开始和函数体的开括号之间的歧义,通常会被使用当你有一个多行返回值。你可以简单地避免使用并将 NavLink 放在同一行中arrow =>

Using ({}) is to destructure the arguments and => () is an implicit return equivalent to => { return ()} and ( only serves to disambiguate between the start of an object and the opening braces of a function body and would generally be used when you have a multiline return value. You could simply avoid using ( and have the NavLink in the same line as the arrow =>

const FilterLink = ({ filter, children }) => ( // <-- implicit return 
  <NavLink
    to={filter === 'SHOW_ALL' ? '/' : `/${ filter }`}
    activeStyle={ {
      textDecoration: 'none',
      color: 'black'
    }}
  >
    {children}
  </NavLink>
)

相当于

const FilterLink = ({ filter, children }) => {
   return (
      <NavLink
        to={filter === 'SHOW_ALL' ? '/' : `/${ filter }`}
        activeStyle={ {
          textDecoration: 'none',
          color: 'black'
        }}
      >
        {children}
      </NavLink>
    )
}

检查有关({filter,children})中解构用法的详细信息

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