使用jquery删除具有特定内容的脚本标记 [英] Removing a script tag with a specific content using jquery

问题描述

我有一个页面，我无法访问其obvius网站。我想删除带有内容的脚本html标记。现在我有这个但是没有用。我正在使用像编码这样的用户脚本！

I have a page that i dont have access to its an obvius site. I would like to remove a script html tag with a content. For now i have this but is not working. I am using userscripts like coding!

function main(){
var def = $('script[type="text/javascript"]').html();
$('script[type="text/javascript"]').each(function() {
if (def == 'document.write("<scr"+"ipt type=\'text/javascript\' src=\'http://storing.com/javascripts/"+(new Date()).getTime()+"/3e155555e1b26c2d1ced0f645e_1_1.js\'></scr"+"ipt>")')
$('script[type="text/javascript"]').remove();
                                                    }
            }

更新：

<script type="text/javascript">document.write("<scr"+"ipt type='text/javascript' src='http://somedomain.com/javascripts/"+(new Date()).getTime()+"/3e1a0cd37f25a6e1b26c2d1ced0f645e_1_1.js'></scr"+"ipt>")</script>

这是我要删除的整个脚本...它插入一个我现在正在删除的div我只是想知道是否有任何其他方法。我看到的只是BUt是hosts文件的东西：）

This is the whole script what i want to remove... it inserts a div that i am removing right now i just wanted to know if there is any other method. BUt as i see the only is the hosts file thing :)

推荐答案

我不相信这会有效，因为加载的脚本已经运行了。

I don't believe this will work, since a loaded script will already have run.

那说，你可能想要这样的东西这个：

That said, you probably want something like this:

$('script').each(function() {
    if (this.src.substring(0, 31) === 'http://storing.com/javascripts/') {
        $(this).remove();
    }
});

无法匹配< script> 标签基于 .html（）的输出，因为它只返回元素的内容，而不是外部< script> 元素和元素的属性。

It's impossible to match the <script> tag based on the output of .html() because that only returns the contents of the element, and not the outer <script> element nor the element's attributes.

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