是否存在通配符导出的语法？ [英] Is there a syntax for wildcard export as?

问题描述

有导入语法：

import * as foo from 'bar';

我同样尝试过：

export * as foo from 'bar';

但是这引发了错误：

ERROR in src/app/@theme/components/aComp/aComp.loader.ts(1,10): error TS1005: 'from' expected.
src/app/@theme/components/aComp/aComp.loader.ts(1,13): error TS1005: ';' expected.
src/app/@theme/components/aComp/aComp.loader.ts(1,17): error TS1005: ';' expected.
src/app/@theme/components/aComp/aComp.loader.ts(1,22): error TS1005: ';' expected.

还有导出语法：

export { default as foo } from 'bar';

有没有办法为 * 而不是默认？

（仅供参考我是试图从语句中删除 require ：

(FYI I'm trying to remove require from the statement):

export const foo = require('bar');

当 ng服务时，会抛出以下错误运行包括上面的 .ts ：

the error below is thrown when ng serve is run including the .ts above:

ERROR in src/app/@theme/components/aComp/aComp.loader.ts(6,20): error TS2304: Cannot find name 'require'.

推荐答案

不，那里不是，但有将此语法添加到语言的提案。

No, there is not, but there is a proposal to add this syntax to the language.

目前，你需要使用

import * as foo from 'bar';
export { foo }; // verbose: { foo as foo }

实际上更接近 export const foo = require（'bar'）; 而不是 export * as foo from'bar'; ，因为它提供 foo 也在本地模块范围内。

which is actually even closer to export const foo = require('bar'); than export * as foo from 'bar';, as it does provide foo in the local module scope as well.

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