匹配正则表达式中的特殊字符和字母 [英] Matching special characters and letters in regex

问题描述

我正在尝试验证字符串，该字符串应仅包含字母数字和特殊字符& -._ 。为此，我尝试使用正则表达式。

I am trying to validate a string, that should contain letters numbers and special characters &-._ only. For that I tried with a regular expression.

var pattern = /[a-zA-Z0-9&_\.-]/
var qry = 'abc&*';
if(qry.match(pattern)) {
    alert('valid');
}
else{
    alert('invalid');
}

使用上面的代码时，字符串 abc& * 有效。但我的要求是显示这个无效。即每当字母，数字或特殊字符& -._ 以外的字符出现时，该字符串应评估为无效。我怎么能用正则表达式做到这一点？

While using the above code, the string abc&* is valid. But my requirement is to show this invalid. ie Whenever a character other than a letter, a number or special characters &-._ comes, the string should evaluate as invalid. How can I do that with a regex?

推荐答案

将它们添加到允许的字符中，但您需要转义它们中的一些，例如 - ] / \

Add them to the allowed characters, but you'll need to escape some of them, such as -]/\

var pattern = /^[a-zA-Z0-9!@#$%^&*()_+\-=\[\]{};':"\\|,.<>\/?]*$/

这样你就可以删除你想要禁止的任何个人角色。

That way you can remove any individual character you want to disallow.

此外，你想要包含一个开头字符串位置标记符结束^和$

Also, you want to include the start and end of string placemarkers ^ and $

更新：

正如elclanrs所理解的那样（而我们其他人最初没有），在模式中需要允许的仅特殊字符是& -._

As elclanrs understood (and the rest of us didn't, initially), the only special characters needing to be allowed in the pattern are &-._

/^[\w&.\-]+$/

[\ w]与[a-zA-Z0-9 _]

[\w] is the same as [a-zA-Z0-9_]

相同虽然破折号不需要转义列表的开头或结尾，我更喜欢这样做，以防其他字符被添加。另外，+ m eans你需要至少一个列出的字符。如果零是好的（即一个空值），然后用*代替它：

Though the dash doesn't need escaping when it's at the start or end of the list, I prefer to do it in case other characters are added. Additionally, the + means you need at least one of the listed characters. If zero is ok (ie an empty value), then replace it with a * instead:

/^[\w&.\-]*$/

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