用正则表达式替换Javascript字符串以去除非法字符 [英] Javascript string replace with regex to strip off illegal characters

问题描述

需要一个功能来解除javascript中的一组非法字符： |& ;; $％@<>（）+，

Need a function to strip off a set of illegal character in javascript: |&;$%@"<>()+,

这是一个需要用正则表达式解决的经典问题，这意味着现在我有2个问题。

This is a classic problem to be solved with regexes, which means now I have 2 problems.

这就是我所拥有的远：

var cleanString = dirtyString.replace(/\|&;\$%@"<>\(\)\+,/g, "");

我正在使用反斜杠逃避正则表达式特殊字符，但我很难理解什么是继续

I am escaping the regex special chars with a backslash but I am having a hard time trying to understand what's going on.

如果我单独尝试使用单个文字它们中的大多数似乎可以工作，但是一旦我将它们放在同一个正则表达式中，取决于命令替换被打破。

If I try with single literals in isolation most of them seem to work, but once I put them together in the same regex depending on the order the replace is broken.

ie这不起作用 - > dirtyString.replace（/ \ |<> / g，）：

i.e. this won't work --> dirtyString.replace(/\|<>/g, ""):

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推荐答案

您需要的是字符类。在那，你只需要担心] ， \ 和 - 字符（以及 ^ 如果你在字符类开头后直接放置它 [）。

What you need are character classes. In that, you've only to worry about the ], \ and - characters (and ^ if you're placing it straight after the beginning of the character class "[" ).

语法： [ 字符 ] 其中个字符是一个包含字符的列表。

Syntax: [characters] where characters is a list with characters.

示例：

var cleanString = dirtyString.replace(/[|&;$%@"<>()+,]/g, "");

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