如何在JavaScript中对字母进行排序，并将大写和小写字母组合在一起？ [英] How do you sort letters in JavaScript, with capital and lowercase letters combined?

问题描述

我正在开发一个JavaScript（jQuery也可以，如果它需要它，但我怀疑它会）用于按字母顺序排列一串字母。假设我要排序的字符串是：ACBacb。

I'm working on a JavaScript (jQuery's OK too if this needs it, but I doubt it will) function to alphabetize a string of letters. Let's say the string that I want to sort is: "ACBacb".

我现在的代码是：

var string='ACBacb';
alert(string.split('').sort().join(''));

这将返回ABCabc。我可以看到为什么会发生这种情况，但这不是我要寻找的格式。有没有办法可以通过将相同的字母放在彼此旁边，首字母大写字母来对其进行排序？所以，当我输入ACBacb时，我得到AaBbCc？

This returns ABCabc. I can see why that happens, but that is not the format that I am looking for. Is there a way that I can sort it by putting the same letters next to each other, capital letter first? So when I put in ACBacb, I get AaBbCc?

推荐答案

Array.sort 可以将sort函数作为可选参数。

Array.sort can have a sort function as optional argument.

首先对字符串进行排序（ACBacbA变为AABCabc），然后将其排序为不区分大小写：

What about sorting the string first (ACBacbA becomes AABCabc), and then sorting it case-insensitive:

function case_insensitive_comp(strA, strB) {
    return strA.toLowerCase().localeCompare(strB.toLowerCase());
}

var str = 'ACBacbA';
// split the string in chunks
str = str.split("");
// sorting
str = str.sort();
str = str.sort( case_insensitive_comp )
// concatenate the chunks in one string
str = str.join("");

alert(str);

根据Felix的建议，第一个排序函数可以省略并合并到第二个排序函数中。首先，对两个字符进行不区分大小写的比较。如果它们相等，请检查它们区分大小写的等效项。返回-1或1表示差异，零表示相等。

As per Felix suggestion, the first sort function can be omitted and merged in the second one. First, do a case-insensitive comparison between both characters. If they are equal, check their case-sensitive equivalents. Return -1 or 1 for a difference and zero for equality.

function compare(strA, strB) {
   var icmp = strA.toLowerCase().localeCompare(strB.toLowerCase());
   if (icmp != 0) {
       // spotted a difference when considering the locale
       return icmp;
   }
   // no difference found when considering locale, let's see whether
   // capitalization matters
   if (strA > strB) {
       return 1;
   } else if (strA < strB) {
       return -1;
   } else {
       // the characters are equal.
       return 0;
   }
}
var str = 'ACBacbA';
str = str.split('');
str = str.sort( compare );
str = str.join('');

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