如何检测非“GSM 7位字母表”输入字段中的字符 [英] How to Detect Non "GSM 7 bit alphabet" characters in input field
问题描述
我正在尝试检测文本输入字段是否包含任何不属于GSM 7位字母表的字符。带有字符的表格在这里 http://www.dreamfabric.com/sms/default_alphabet.html
I am trying to detect if a text input field has any character that doesn't belong to the GSM 7 bit alphabet. The table with the characters is here http://www.dreamfabric.com/sms/default_alphabet.html
经过大量搜索后我发现了这一点(我需要用什么正则表达式检查一些非拉丁字符?)它非常接近我想要的完成因为它检测非拉丁字符。如何更改正则表达式以包含GSM 7位字母?
After a lot of searching I found this (What regular expression do I need to check for some non-latin characters?) that its pretty close to what I want to accomplish because It detects Non latin characters. How can I alter the regular expression to include the GSM 7 bit alphabet?
<!DOCTYPE HTML>
<html lang="en-US">
<head>
<meta charset="UTF-8">
<title>test foreign chars</title>
</head>
<body>
<input id="foreign_characters" size="12" type="text" name="foreign_characters" value="test">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.8.2/jquery.min.js"></script>
<script type="text/javascript">
(function(){
$('#foreign_characters').on("keyup", function(){
var foreignCharacters = $("#foreign_characters").val();
var rforeign = /[^\u0000-\u007f]/;
if (rforeign.test(foreignCharacters)) {
alert("This is non-Latin Characters");
} else {
alert("This is Latin Characters");
}
});
})();
</script>
</body>
</html>
推荐答案
您可以将所有有效字符放入字符串中然后重复搜索字符串。
You can put all valid characters in a string and then search the string repeatedly.
gsm = "@£$¥èéùìòÇØøÅåΔ_ΦΓΛΩΠΨΣΘΞ^{}\[~]|€ÆæßÉ!\"#¤%&'()*+,-./0123456789:;<=>?¡ABCDEFGHIJKLMNOPQRSTUVWXYZÄÖÑܧ¿abcdefghijklmnopqrstuvwxyzäöñüà";
var letter = 'a';
var letterInAlfabet = gsm.indexOf(letter) !== -1;
如果你确定你的编码是正确的使用它,即将您的Javascript文件保存为UTF8,并指定它是浏览器的UTF8 。
Make sure you get your encodings right if you use this, i.e. save your Javascript file as UTF8 and specify that it is UTF8 to the browser.
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