在不使用变量名的情况下打印嵌套的JSON [英] Printing nested JSON without using variable names

问题描述

Web服务返回以下嵌套的json对象：

a web service returns the following nested json object:

{"age":"21-24","gender":"Male","location":"San Francisco, CA","influencer score":"70-79","interests":{"Entertainment":{"Celebrities":{"Megan Fox":{},"Michael Jackson":{}},},"Social Networks & Online Communities":{"Web Personalization": {},"Journals & Personal Sites": {},},"Sports":{"Basketball":{}},},"education":"Completed Graduate School","occupation":"Professional/Technical","children":"No","household_income":"75k-100k","marital_status":"Single","home_owner_status":"Rent"}

我只想迭代遍历此对象指定属性名称，我尝试了以下代码：

i just want to iterate through this object without specifying property name, i tried the following code :

for (var data in json_data) {
    alert("Key:" + data + " Values:" + json_data[data]);
}

但如果它是一个嵌套值，它会将值打印为[object Object]，有没有办法继续深入迭代嵌套值？

however it prints value as [object Object] if it's a nested value, is there any way to keep iterating deeper into nested values ?

推荐答案

试试这个：

function iter(obj) {
  for (var key in obj) {
    if (typeof(obj[key]) == 'object') {
      iter(obj[key]);
    } else {
      alert("Key: " + key + " Values: " + obj[key]);
    }
  }
}

BB：添加+以防止错误。

BB: added + to prevent error.

这篇关于在不使用变量名的情况下打印嵌套的JSON的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！