使用Javascript中的RegExp在开始/结束时删除重复的逗号和额外的逗号，并删除重复的数字？ [英] Remove duplicate commas and extra commas at start/end with RegExp in Javascript, and remove duplicate numbers?

问题描述

假设我们有一个如下字符串：

Assume we have a string like the following :

,34,23,4,5,634,23,12,5,4,3,1234,23,54,,,,,,,123,43,2,3,4,5,3424,,,,,,,,123,,,1234,,,,,,,45,,,56

如何在Javascript中使用RegExp将其转换为以下字符串？

How can we convert it to the following string with RegExp in Javascript ?

34,23,4,5,634,12,3,1234,54,123,43,2,3424,45,56

实际上，我想删除重复的项目，并且首先和最后， char

Actually, I wanna remove repeated items and first and last , char

推荐答案

要将这些变为一组唯一数字，正如您实际要求的那样，请执行以下操作：

[edited] To turn these into a set of unique numbers, as you are actually asking for, do this:

function scrapeNumbers(string) {
    var seen = {};
    var results = [];
    string.match(/\d+/g).forEach(function(x) {
        if (seen[x]===undefined)
            results.push(parseInt(x));
        seen[x] = true;
    });
    return results;
}

演示：

> scrapeNumbers(',1,22,333,22,,333,4,,,')
[1, 22, 333, 4]

如果您有一个 Array.prototype.unique（）原语，您可以将它写成一行：

If you had an Array.prototype.unique() primitive, you could write it like so in one line:

yourString.match(/\d+/g).map(parseBase10).unique()

不幸的是你需要有点冗长并定义你自己的 parseBase10 = function（n）{return parseInt（n） } 由于这个荒谬的难以追踪的错误： javascript - Array＃map和parseInt

Unfortunately you need to be a bit verbose and define your own parseBase10 = function(n){return parseInt(n)} due to this ridiculous hard-to-track-down bug: javascript - Array#map and parseInt

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