正则表达式用空格分割字符串，考虑嵌套括号 [英] Regex split string by spaces taking into account nested brackets

问题描述

我知道这已被多次询问/回答，但不幸的是，到目前为止，我尝试过的解决方案都没有。
我需要拆分这样的东西：

I know that this has been asked/answered several times but unfortunately none of the solutions I've tried so far works in my case. I need to split something like this:

contrast(200%) drop-shadow(rgba(0, 0, 0, 0.5) 0px 0px 10px)

进入：

contrast(200%)
drop-shadow(0px 0px 10px rgba(0,0,0,.5))

通过关注这个解决方案，我现在正在这样做：

By following this solution, I'm currently doing this:

myString = "contrast(200%) drop-shadow(rgba(0, 0, 0, 0.5) 0px 0px 10px)"
myString.match(/[^\(\s]+(\(.*?\)+)?/g)

但是这给了我：

contrast(200%)
drop-shadow(rgba(0, 0, 0, 0.5)  <== notice the missing second ) here
0px    <== unwanted, should go with previous one
0px    <== unwanted, should go with previous one
10px)  <== unwanted, should go with previous one

因为正则表达式没有捕获所有结束括号...

as the regexp does not capture all closing brackets...

推荐答案

这是我的解决方案：

function splitBySpaces(string){
    var openBrackets = 0, ret = [], i = 0;
    while (i < string.length){
        if (string.charAt(i) == '(')
            openBrackets++;
        else if (string.charAt(i) == ')')
            openBrackets--;
        else if (string.charAt(i) == " " && openBrackets == 0){
            ret.push(string.substr(0, i));
            string = string.substr(i + 1);
            i = -1;
        }
        i++;
    }

    if (string != "") ret.push(string);
    return ret;
}

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