仅在分隔符的前n次出现时拆分字符串 [英] Split a string only the at the first n occurrences of a delimiter
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问题描述
我想仅在分隔符的前n次出现时拆分字符串。我知道,我可以使用循环将它们添加到一起,但是没有更直接的方法吗?
I'd like to split a string only the at the first n occurrences of a delimiter. I know, I could add them together using a loop, but isn't there a more straight forward approach?
var string = 'Split this, but not this';
var result = new Array('Split', 'this,', 'but not this');
推荐答案
根据 MDN :
string.split(separator, limit);
更新:
var string = 'Split this, but not this',
arr = string.split(' '),
result = arr.slice(0,2);
result.push(arr.slice(2).join(' ')); // ["Split", "this,", "but not this"]
更新版本2(一个切片
更短):
Update version 2 (one slice
shorter):
var string = 'Split this, but not this',
arr = string.split(' '),
result = arr.splice(0,2);
result.push(arr.join(' ')); // result is ["Split", "this,", "but not this"]
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