从内部引用javascript函数 [英] Refer to javascript function from within itself

问题描述

考虑这段代码

  var crazy = function（）{
 console.log（this）; 
 console.log（this.isCrazy）; //错了。 
} 
 crazy.isCrazy ='完全'; 
 crazy（）; 
 // ouput => 
 // DOMWindow 
 // undefined 
  

从疯狂（）里面这个'指的是窗口，我想这是有意义的，因为通常你想要这个引用函数所附加的对象，但是如何让函数引用自身，并访问自身的属性集？ / p>

答案：

不要使用arguments.callee，只需使用命名函数。

注意：你应该避免使用arguments.callee（），只需给每个函数（表达式）命名。通过关于arguments.callee的MDN文章

解决方案

我认为你要求arguments.callee，但现在已弃用。

https：// developer。 mozilla.org/en/JavaScript/Reference/Functions_and_function_scope/arguments/callee

  var crazy = function（）{ 
 console.log（this）; 
 console.log（arguments.callee.isCrazy）; // 对。 
} 
 crazy.isCrazy ='完全'; 
 crazy（）; 
 // ouput => 
 // DOMWindow 
 //总计
  

Consider this piece of code

var crazy = function() {
    console.log(this);
    console.log(this.isCrazy); // wrong.
}
crazy.isCrazy = 'totally';
crazy();
// ouput =>
// DOMWindow
// undefined

From inside crazy() 'this' refers to the window, which I guess makes sense because normally you'd want this to refer to the object the function is attached to, but how can I get the function to refer to itself, and access a property set on itself?

Answer:

Don't use arguments.callee, just use a named function.

"Note: You should avoid using arguments.callee() and just give every function (expression) a name." via MDN article on arguments.callee

解决方案

I think you are asking for arguments.callee, but it's deprecated now.

https://developer.mozilla.org/en/JavaScript/Reference/Functions_and_function_scope/arguments/callee

var crazy = function() {
    console.log(this);
    console.log(arguments.callee.isCrazy); // right.
}
crazy.isCrazy = 'totally';
crazy();
// ouput =>
// DOMWindow
// totally

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