发生未捕获的异常时重新启动Node.js应用程序 [英] Restart Node.js application when uncaught exception occurs

问题描述

如果发生异常，我怎么能重启我的应用程序？

How would I be able to restart my app when an exception occurs?

process.on('uncaughtException', function(err) {         
  // restart app here
});

推荐答案

您可以将该流程作为另一个流程的分支运行，所以如果它死了就可以分叉。您可以使用原生群集模块：

You could run the process as a fork of another process, so you can fork it if it dies. You would use the native Cluster module for this:

var cluster = require('cluster');
if (cluster.isMaster) {
  cluster.fork();

  cluster.on('exit', function(worker, code, signal) {
    cluster.fork();
  });
}

if (cluster.isWorker) {
  // put your code here
}

此代码生成一个工作进程，如果在工作进程中抛出错误，它将关闭，退出将重新生成另一个工作进程。

This code spawns one worker process, and if an error is thrown in the worker process, it will close, and the exit will respawn another worker process.

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