如何使用jQuery.grep（）过滤多维JSON对象 [英] How to filter a Multi-dimension JSON object with jQuery.grep()

问题描述

我有一个JSON对象，如下所示：

I have a JSON object that goes like this:

{"data":
 [
  {"name":"Alan","height":"171","weight":"66"},
  {"name":"Ben","height":"182","weight":"90"},
  {"name":"Chris","height":"163","weight":"71"}
 ]
 ,"school":"Dover Secondary"
}

我想过滤JSON对象以获取数据那些高于170且重于70的人，然后对这个物体进行排序。从 jQuery网站中，我了解到可以在线性阵列上轻松实现过滤，例如：

I would like to filter the JSON object to obtain data of those taller than 170 and heavier than 70 and subsequently sort this object. From the jQuery website, I understand that filtering would be easily achieved on a linear array with something like:

arr = jQuery.grep(arr, function(element, index){
  return (element > 70 && index = 'weight');
});

如何同时过滤体重和身高以获得此效果：

How do I filter both weight and height concurrently to get this:

{"data":
 [
  {"name":"Ben","height":"182","weight":"90"},
 ]
 ,"school":"Dover Secondary"
}

推荐答案

我认为你的意思是： http://jsfiddle.net / NRuM7 / 1 / 。

var obj = {"data":
 [
  {"name":"Alan","height":"171","weight":"66"},
  {"name":"Ben","height":"182","weight":"90"},
  {"name":"Chris","height":"163","weight":"71"}
 ]
 ,"school":"Dover Secondary"
};

obj.data = jQuery.grep(obj.data, function(element, index){
  return element.weight > 70 && element.height > 170; // retain appropriate elements
});

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