如何用回调编写jQuery函数? [英] How to write a jQuery function with a callback?
本文介绍了如何用回调编写jQuery函数?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有以下功能:
function loadProjects(pID) {
$.ajax({
url: myURL,
success: function (dataJS) {XXXXXXXXXXXXXXXX}
});
}
我将此函数称为loadProjects(1);
I call this function like so loadProjects(1);
问题是我希望能够在成功后定义一个callBack函数,并且我想在我执行loadProjects时包含它(1,回调:{此处包含的任何js被调用成功后回来})
Issue is I want to be able to define a callBack function after success, and I'd like to include it when I do loadProjects(1, callback:{whatever js is included here gets called back after success})
我如何让函数接受回调?
如何将回调传递给该函数?
How can I have a function accept a callback? How can I pass a callback to that function?
谢谢
推荐答案
function loadProjects(pID, callbackFunction)
{
$.ajax({
url: myURL,
success: function (dataJS)
{
if(typeof callbackFunction == 'function')
{
callbackFunction.call(this, dataJS);
}
}
});
}
用法:
loadProjects(pID, function(dataJS)
{
// do stuff with your dataJS, bear in mind you can call the parameter any name.
});
这篇关于如何用回调编写jQuery函数?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文