在underscore.js中展平嵌套数组/对象 [英] flattening nested arrays/objects in underscore.js
问题描述
我有一个对象数组,如下所示(尽管下面的例子只有数组中的一个元素)
[
{
正常运行时间:0,
加载:{x:0.11,y:0.22,z:0.33},
cpu :[
{u:111,n:112,s:113,i:114,q:115},
{u:211, n:212,s:213,i:214,q:215}
]
}
]
我试图使用underscore.js来展平每个元素,所以整个数组看起来像这样:
[
{
正常运行时间:0,
load_x:0.11
load_y:0.03
load_z:0.01,
cpu1_u:111,
cpu1_n:112,
cpu1_s:113,
cpu1_i :114,
cpu1_q:115,
cpu2_u:211,
cpu2_n:212,
cpu2_s:213,
cpu2_i:214,
cpu2_q:215,
}
]
我已经对'load'元素进行了排序(虽然不是一般),因为那只是一个已知的3字段对象。 / p>
扁平化cpu阵列虽然暗示了我。
我的代码如下,以及我的代码生成的输出
我知道我可以写一个js循环并完成它,但我见过一些非常优雅的下划线解决方案,我确信这是可能的。
有什么建议吗?
我的代码
var profiles = [
{
uptime:0,
load:{x:0.11,y:0.22,z: 0.33},
cpu:[
{u:111,n:112,s:113,i:114,q:115},
{你:211,n:212,s:213,i:214,q:215}
]
}
];
var flat = _.map(profiles,function(profile){
var p = _.extend(_。omit(profile,'load'),{
load_1 :Math.round(100 * profile.load.x)/ 100,
load_5:Math.round(100 * profile.load.y)/ 100,
load_15:Math.round(100 * profile .load.z)/ 100
});
var cpuid = 0;
var cpuobject =
_.map(p.cpu,function(cpu) {
cpuid ++;
返回_.object(
_.map(cpu,function(val,key){
var arr = ['cpu'+ cpuid +'_'+ key,val];
return arr;
})
);
});
返回_.extend(_。省略(p,'cpu') ,cpuobject);
});
console.log(JSON.stringify(flat));
我的(错误)输出
[
{
0:{
cpu1_u:233264700,
cpu1_n:0,
cpu1_s: 64485200,
cpu1_i:1228073616,
cpu1_q:86100
},
1:{
cpu2_u:233264700,
cpu2_n:0,
cpu2_s:64485200,
cpu2_i:1228073616,
cpu2_q:86100
},
正常运行时间:0,
load_1:0.11,
load_5:0.03,
load_15:0.01
}
]
例如:
flatten = function(x,result,prefix){
if(_ .isObject(x)){
_.each(x,function(v,k){
flatten(v,result,prefix?prefix +'_'+ k:k)
})
} else {
result [prefix] = x
}
返回结果
}
a =
{
正常运行时间:0,
加载:{x :0.11,y:0.22,z:0.33},
cpu:[
{u:111,n:112,s:113,i :114,q:115},
{u:211,n:212,s:213,i:214,q:215}
]
}
result = flatten(a,{})
{
正常运行时间:0,
load_x:0.11,
load_y:0.22,
load_z:0.33,
cpu_0_u:111,
cpu_0_n:112,
cpu_0_s:113,
cpu_0_i:114,
cpu_0_q:115,
cpu_1_u:211,
cpu_1_n:212,
cpu_1_s:213,
cpu_1_i:214,
cpu_1_q:215
}
I have an array of objects as shown below (although the example below has just one element in the array)
[
{
"uptime":0,
"load":{"x":0.11,"y":0.22,"z":0.33},
"cpu":[
{"u":111,"n":112,"s":113,"i":114,"q":115},
{"u":211,"n":212,"s":213,"i":214,"q":215}
]
}
]
Im trying to flatten out each element using underscore.js, so the overall array looks like this:
[
{
"uptime":0,
"load_x": 0.11
"load_y": 0.03
"load_z": 0.01,
"cpu1_u": 111,
"cpu1_n": 112,
"cpu1_s": 113,
"cpu1_i": 114,
"cpu1_q": 115,
"cpu2_u": 211,
"cpu2_n": 212,
"cpu2_s": 213,
"cpu2_i": 214,
"cpu2_q": 215,
}
]
I've got the 'load' element sorted (albeit not generically), since thats just a known 3 field object.
Flattening the cpu array alludes me though. My code is below, along with the output my code is generating
I know I could just write a js loop and be done with it, but Ive seen some very elegant underscore solutions like this, and Im sure its possible. Any advice please?
My Code
var profiles = [
{
"uptime":0,
"load":{"x":0.11,"y":0.22,"z":0.33},
"cpu":[
{"u":111,"n":112,"s":113,"i":114,"q":115},
{"u":211,"n":212,"s":213,"i":214,"q":215}
]
}
];
var flat = _.map(profiles, function(profile) {
var p = _.extend(_.omit(profile, 'load'), {
load_1: Math.round(100*profile.load.x)/100,
load_5: Math.round(100*profile.load.y)/100,
load_15: Math.round(100*profile.load.z)/100
});
var cpuid = 0;
var cpuobject =
_.map(p.cpu, function(cpu) {
cpuid++;
return _.object(
_.map(cpu, function(val, key) {
var arr = ['cpu'+cpuid+'_'+key, val];
return arr;
})
);
});
return _.extend(_.omit(p, 'cpu'), cpuobject);
});
console.log(JSON.stringify(flat));
My (Wrong) Output
[
{
0: {
cpu1_u: 233264700,
cpu1_n: 0,
cpu1_s: 64485200,
cpu1_i: 1228073616,
cpu1_q: 86100
},
1: {
cpu2_u: 233264700,
cpu2_n: 0,
cpu2_s: 64485200,
cpu2_i: 1228073616,
cpu2_q: 86100
},
uptime: 0,
load_1: 0.11,
load_5: 0.03,
load_15: 0.01
}
]
For example:
flatten = function(x, result, prefix) {
if(_.isObject(x)) {
_.each(x, function(v, k) {
flatten(v, result, prefix ? prefix + '_' + k : k)
})
} else {
result[prefix] = x
}
return result
}
a =
{
"uptime":0,
"load":{"x":0.11,"y":0.22,"z":0.33},
"cpu":[
{"u":111,"n":112,"s":113,"i":114,"q":115},
{"u":211,"n":212,"s":213,"i":214,"q":215}
]
}
result = flatten(a, {})
{
"uptime": 0,
"load_x": 0.11,
"load_y": 0.22,
"load_z": 0.33,
"cpu_0_u": 111,
"cpu_0_n": 112,
"cpu_0_s": 113,
"cpu_0_i": 114,
"cpu_0_q": 115,
"cpu_1_u": 211,
"cpu_1_n": 212,
"cpu_1_s": 213,
"cpu_1_i": 214,
"cpu_1_q": 215
}
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