如何在javascript函数调用中实现任意链? [英] How to achieve arbitrary chain on function call in javascript?
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问题描述
我已经编写了代码来实现
I have written code to achieve
sum(1)(2) //3
代码如下:
function sum(a) {
return function(b) {
return a+b
}
}
但我没有解决第二个问题,即如何实现任意数量的链函数调用,如:
But I didn't work out the second question, which is how to achieve any arbitrary number of chain function call like:
sum(1)(2) == 3
sum(5)(-1)(2) == 6
sum(6)(-1)(-2)(-3) == 0
sum(0)(1)(2)(3)(4)(5) == 15
推荐答案
通常你会这样做:
var add = function(a,b){
return a+b;
};
var sum = function(){
return [].reduce.call(arguments, add);
}
然后你可以写:
sum(1,2,3,4); // 10
但是有可能破解你所追求的功能:
But it is possible to hack the functionality you're after:
var sum = function(x){
var f = function(y){
return sum(x+y);
};
f.valueOf = function(){
return x;
};
return f;
};
sum(1)(2)(3)(4); // 10
请不要在生产代码中执行此操作!
Just don't do it in production code please!
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