是否Console.WriteLine块？ [英] Does Console.WriteLine block?

问题描述

确实 Console.WriteLine 块，直到输出已被写入或不会立即返回？

如果它确实是块写有异步输出到控制台的方法？

解决方案

  

确实Console.WriteLine块，直到   输出已被写入或做它   立即返回？

是的。

  

如果它确实是块有一个方法   编写异步输出到   控制台？

要解决写到控制台没有阻塞是出奇的平凡的，如果您使用的是.NET 4.0。我们的想法是要排队文本值，让一个专门的线程执行 Console.WriteLine 通话。生产者 - 消费者模式是理想的位置，因为它preserves时间顺序使用本机控制台上课的时候​​是隐含的。之所以.NET 4.0，使这个简单是因为它具有 BlockingCollection 类，它有利于生产生产者 - 消费者模式。如果您不使用.NET 4.0，那么你可以通过下载href="http://msdn.microsoft.com/en-us/devlabs/ee794896.aspx" rel="nofollow">无扩展的框架。

 公共静态类NonBlockingConsole
{
  私有静态BlockingCollection＆LT;字符串＆GT; m_Queue =新BlockingCollection＆LT;字符串＆GT;（）;

  静态NonBlockingConsole（）
  {
    VAR线程=新主题（
      （）=＆GT;
      {
        而（真）Console.WriteLine（m_Queue.Take（））;
      }）;
    thread.IsBackground = TRUE;
    thread.Start（）;
  }

  公共静态无效的WriteLine（字符串值）
  {
    m_Queue.Add（值）;
  }
}
 

Does Console.WriteLine block until the output has been written or does it return immediately?

If it does block is there a method of writing asynchronous output to the Console?

解决方案

Does Console.WriteLine block until the output has been written or does it return immediately?

Yes.

If it does block is there a method of writing asynchronous output to the Console?

The solution to writing to the console without blocking is surprisingly trivial if you are using .NET 4.0. The idea is to queue up the text values and let a single dedicated thread do the Console.WriteLine calls. The producer-consumer pattern is ideal here because it preserves the temporal ordering that is implicit when using the native Console class. The reason why .NET 4.0 makes this easy is because it has the BlockingCollection class which facilitates the production of a producer-consumer pattern. If you are not using .NET 4.0 then you can get a backport by downloading the Reactive Extensions framework.

public static class NonBlockingConsole
{
  private static BlockingCollection<string> m_Queue = new BlockingCollection<string>();

  static NonBlockingConsole()
  {
    var thread = new Thread(
      () =>
      {
        while (true) Console.WriteLine(m_Queue.Take());
      });
    thread.IsBackground = true;
    thread.Start();
  }

  public static void WriteLine(string value)
  {
    m_Queue.Add(value);
  }
}

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