Php ajax用新数组上传多个文件 [英] Php ajax multiple file upload with new array

问题描述

我的上传html代码;

its mine upload html code ;

 <div class="col-xs-12">
    <label for="upload" class="btn btn-sm btn-outline green btn-block">
       <i  class="fa fa-upload"></i>
       upload
   </label><input type="file" multiple id="upload"  class="hidden"/>
 </div>

更改方法的文件元素

 $("#upload").change(function (event) {
            var files = event.target.files;
            files = Object.values(files);
            files.forEach(function (file) {
                if (file.type.match('image')
                    || file.type.match('application/vnd.ms-excel')
                    || file.type.match('application/pdf')
                    || file.type.match('application/vnd.openxmlformats-officedocument.wordprocessingml.document')
                    || file.type.match('application/vnd.openxmlformats-officedocument.presentationml.presentation')
                ) {
                    uploadingFile.push(file);
                }
            });
        });

单击上传按钮时的Ajax代码..

Ajax code when click upload button..

var myFormData = new FormData();
        uploadingFile.forEach(function (file) {
            myFormData.append('myFiles', file);
        });
        myFormData.append('a', 1);
        $.ajax({
            url: 'ajax/upload.php',
            type: 'POST',
            processData: false, // important
            contentType: false, // important
            data: myFormData,success: function(data, textStatus, jqXHR)
            {
              console.log(data);
            }
        });

最后的代码是php代码;

And Last of code is php code;

    $myFiles=$_FILES["myFiles"];

for($i=0; $i<count($myFiles); $i++){
    $target_path = "uploaded_files/";
    print_r($myFiles[$i]);
    echo $myFiles[$i]["tmp_name"]."\n";
    $ext = explode('.',$myFiles[$i]["tmp_name"]);
    $target_path = $target_path . md5(uniqid()) . "." . $ext[count($ext)-1];

    $sonuc=move_uploaded_file($myFiles[$i], $target_path);
    if(move_uploaded_file($myFiles[$i], $target_path)) {
        echo "The file has been uploaded successfully \n";
    } else{
        echo "There was an error uploading the file, please try again! \n";
    }
}

运行代码时收到此消息。上传文件时出错，请重试！我想将多个文件上传到带有数组的服务器。为什么我需要一个数组，因为我删除了数组中的一些文件，我想将数组的最后结果上传到服务器。

i get this message when run the code. There was an error uploading the file, please try again! I want to upload multiple file to server with array. Why i need an array because I delete some file in array and i want to upload last result of array to server.

我的错是什么？我没有找到任何东西。

What is my fault ? I didn't find anything.

$ myFiles [$ i]是一个空对象。

The $myFiles[$i] is a null object.

推荐答案

您使用以下代码行附加单个文件 myFormData.append（'myFiles'，file） ; 。您必须使用此代码 myFormData.append（'myFiles []'，file）; 来发送多个文件。下面是我已经实现的可以上传多个文件的代码。

You are appending single file using this line of code myFormData.append('myFiles', file);. You have to use this code myFormData.append('myFiles[]', file); to send multiple file. Below is the code that i have implemented which can upload multiple files.

在代码下面的脚本位置。

in your script place below code.

<script type="text/javascript">
    $("#upload").change(function (event) {
        var files = event.target.files;
        var uploadingFile = [];
        files = Object.values(files);
        files.forEach(function (file) {
            if (file.type.match('image')
                || file.type.match('application/vnd.ms-excel')
                || file.type.match('application/pdf')
                || file.type.match('application/vnd.openxmlformats-officedocument.wordprocessingml.document')
                || file.type.match('application/vnd.openxmlformats-officedocument.presentationml.presentation')
            ) {
                uploadingFile.push(file);
            }
        });

        var myFormData = new FormData();
        uploadingFile.forEach(function (file) {
            myFormData.append('myFiles[]', file);
        });

        $.ajax({
            url: 'upload.php',
            type: 'POST',
            processData: false, // important
            contentType: false, // important
            data: myFormData,success: function(data, textStatus, jqXHR)
            {
              console.log(data);
            }
        });
    });
</script>

在您上传的代码下方的PHP代码中。

And in your upload php code place below code.

$target_path = "uploaded_files/";

$myFiles=$_FILES["myFiles"];
if(count($myFiles['name']) > 1){
    $total = count($myFiles['name']);
    for($i=0; $i<$total; $i++){
        $ext = explode('.',$myFiles["name"][$i]);
        $target_path = $target_path . md5(uniqid()) . "." . $ext[count($ext)-1];

        if(move_uploaded_file($myFiles["tmp_name"][$i], $target_path)) {
            echo "The file has been uploaded successfully \n";
        } else{
            echo "There was an error multiple uploading the file, please try again! \n";
        }
    }
} else {
    $ext = explode('.',$myFiles["name"]);
    $target_path = $target_path . md5(uniqid()) . "." . $ext[count($ext)-1];

    if(move_uploaded_file($myFiles["tmp_name"], $target_path)) {
        echo "The file has been uploaded successfully \n";
    } else{
        echo "There was an error uploading the file, please try again! \n";
    }
}

这篇关于Php ajax用新数组上传多个文件的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！