将JSON发送到Spring MVC控制器 [英] Sending JSON to Spring MVC controller

查看:71
本文介绍了将JSON发送到Spring MVC控制器的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试将JSON发送到Spring MVC Controller。在Spring MVC方面,一切都配置正确。

I am trying to send JSON to a Spring MVC Controller. On the Spring MVC side, everything is configured correctly.

以下是代码,但似乎没有运行:

Below is the code but doesn't seem to run:

<html>
<head>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>  
<script type="text/javascript">
  $('#myForm').on('submit', function(e) { 
    e.preventDefault(); 
    var frm = $("#myForm"); 
    var dat = frm.serialize(); 
    $.ajax({ 
    type: 'POST', 
    url: $('#myForm').attr('action'), 
    data: dat, 
    contentType: 'application/json' 
    success: function(hxr) { 
        alert("Success: " + xhr); 
    } 
}); 
});   
 </script>   
</head>
<body>
<h2>Application</h2>
<form id="myForm" action="/application/save" method="POST" accept="application/json" onclick="i()">
                <input type="text" name="name" value="myName">
    <input type="submit" value="Submit">
</form>


在Tomcat中我收到以下错误:

In Tomcat I get the following error:


org.springframework.web.servlet.mvc.support.DefaultHandlerE
xceptionResolver handleNoSuchRequestHandlingMethod
警告:没有为servlet请求找到匹配的处理程序方法:path'/ application / save',方法'POST',参数map ['name' - > array ['myName']]

org.springframework.web.servlet.mvc.support.DefaultHandlerE xceptionResolver handleNoSuchRequestHandlingMethod WARNING: No matching handler method found for servlet request: path '/application/save', method 'POST', parameters map['name' -> array['myName']]

我出错的任何想法?我是JSON的新手。我试图将JSON发送到Spring MVC控制器。

Any ideas where I am going wrong? I am new to JSON. I am trying to to send JSON to Spring MVC controller.

@Controller
@RequestMapping("/run/*")
public class HistoryController {

    @RequestMapping(value = "save", method = RequestMethod.POST, headers = {"content-type=application/json"})
public @ResponseBody Response save(@RequestBody User user) throws Exception {
    Response userResponse = new Response();
    System.out.println("UserId :" + " " + user.getName());
    return userResponse;
}
}

@RequestMapping(value = "find", method = RequestMethod.GET)
public @ResponseBody Response find() {
    System.out.println("Run");
    Response userResponse = new Response();
    userResponse.setVersionNumber("1.0");
    return userResponse;
}

当调用/ application / run / save时,我得到一个JSON响应。但是@RequestBody不起作用。

When invoking /application/run/save I get a JSON response. However the @RequestBody does not work.

我仍然没有运气。已经阅读了许多类似的问题。要求是服务器只接受application / json类型。我正在使用Spring MVC控制器。如前所述,代码通过@ResponseBody将响应作为JSON发回。我想通过Spring MVC Controller中的@RequestBody获取信息。我正在使用JSP将JSON发送到Spring MVC Controller。我的代码和Spring MVC可以在下面看到:

I still have had no luck. Have read some many similiar problems. The requirement is that the server will only accept application/json types. I am using a Spring MVC Controller. As mentioned earlier, the code sends a response back as JSON through @ResponseBody. I want to get information through the @RequestBody in my Spring MVC Controller. I am using JSP to send JSON to Spring MVC Controller. My code and Spring MVC can be seen below:

我是JSON和Javascript的新手。

I am new to JSON and Javascript.

JSP - index.jsp

JSP - index.jsp

<%@page language="java" contentType="text/html"%>
<html>
<head>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>  
<script type="text/javascript">
    $('#myForm').on('submit', function(e) { 
    var frm = $("#myForm");
   var dat = JSON.stringify(frm.serializeArray()); 

$.ajax({ 
     type: 'POST', 
     url: $('#myForm').attr('action'), 
     data: dat,
     contentType: 'application/json',
     dataType: 'json',
     error: function() {
        alert('failure');
     }
     success: function(hxr) { 
         alert("Success: " + xhr); 
     }
  }); 
); 
}; 
</script> 
</head>
<body>
<h2>Application</h2>
<form id="myForm" action="/application/save" method="POST" accept="application/json" onclick="i()">
    <input type="text" name="userId" value="User">
    <input type="submit" value="Submit">
</form>
</body>
</html>

运行时我没有得到任何输出。在Chrome中我收到404 Not found错误,在Tomcat中我收到以下错误:

When running this I am not getting any output. In the Chrome I get 404 Not found error and in Tomcat I get the following error:

org.springframework.web.servlet.mvc.support.DefaultHandlerExceptionResolver     handleNoSuchRequestHandlingMethod
WARNING: No matching handler method found for servlet request: path '/application/sa
 ve', method 'POST', parameters map['userId' -> array<String>['User']]

JSP部分有什么问题吗?

Is something wrong here in the JSP part?

web.xml

<?xml version="1.0" encoding="UTF-8"?> 
<web-app xmlns="http://java.sun.com/xml/ns/j2ee"
     xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
     xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_5.xsd"
     version="2.5">

     <display-name>WebApp</display-name>

     <context-param>
        <!-- Specifies the list of Spring Configuration files in comma separated format.-->
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/spring/service.xml</param-value>
     </context-param>

     <listener>
        <!-- Loads your Configuration Files-->
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
     </listener>

     <servlet>
        <servlet-name>application</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
     </servlet>

     <servlet-mapping>
        <servlet-name>application</servlet-name>
        <url-pattern>/</url-pattern>
     </servlet-mapping>

     <welcome-file-list>
        <welcome-file>index.jsp</welcome-file>
     </welcome-file-list>    
</web-app>

service.xml

service.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:util="http://www.springframework.org/schema/util"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
    http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd
    http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
    http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util-3.0.xsd">

    <context:component-scan base-package="com.web"/>

    <mvc:annotation-driven/>

    <context:annotation-config/>

    <bean class="org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping"/>

    <bean id="jacksonMessageChanger" class="org.springframework.http.converter.json.MappingJacksonHttpMessageConverter">
        <property name="supportedMediaTypes" value="application/json"/>
    </bean>

    <!-- <bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter">
        <property name="messageConverters">
            <list>
                <ref bean="jacksonMessageChanger"/>
            </list>
        </property>
    </bean>-->

    <bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter">
        <property name="messageConverters">
            <util:list id="beanList">
                <ref bean="jacksonMessageChanger"/>
            </util:list>
        </property>
    </bean>

    <bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
        <property name="prefix" value="/WEB-INF/jsp/"/>
        <property name="suffix" value=".jsp"/>
    </bean>

    <!-- <bean class="org.springframework.web.servlet.view.ContentNegotiatingViewResolver">
        <property name="mediaTypes">
            <map>
                <entry key="json" value="application/json"/>
            </map>
        </property>
    </bean>-->  
</beans>

控制器

package com.web;

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.ResponseBody;
import org.springframework.web.bind.annotation.RequestBody;
import com.webchannel.domain.User;
import com.webchannel.domain.UserResponse;

@Controller
@RequestMapping("/application/*")
public class SaveController {

@RequestMapping(value = "save", method = RequestMethod.POST, headers = {"content-type=application/json"})
public @ResponseBody UserResponse save(@RequestBody User user) throws Exception {
    UserResponse userResponse = new UserResponse();
    System.out.println("UserId :" + " " + user.getUserId());
    return userResponse;
}

@RequestMapping(value = "delete", method = RequestMethod.GET)
public @ResponseBody UserResponse delete() {
    System.out.println("Delete");
    UserResponse userResponse = new UserResponse();
    userResponse.setSuccess(true);
    userResponse.setVersionNumber("1.0");
    return userResponse;
}
}

调用/ application / delete时,我会返回JSON。所以我知道我的JacksonProcessor配置正确。问题出在@RequestBody。

When invoking /application/delete I get JSON returned. So I know my JacksonProcessor is configured correctly. The problem is in @RequestBody.

我哪里错了?请帮帮我。

Where am I going wrong? Please help me.

推荐答案

我想你可能需要做一些改变

I think you may need make couple of changes


  1. 由于您的控制器有 @RequestMapping(/ run / *),您可能需要将其更改为 @RequestMapping(/ run /)并且在jsp表单操作中,您可能需要更改< form id =myFormaction =/ application / run / savemethod =POSTaccept =application / jsononclick =i()> ,因为你已经定义了 @RequestMapping(value =为控制器中的'save`方法保存,method = RequestMethod.POST,headers = {content-type = application / json})

  1. Since your controller has @RequestMapping("/run/*"), you may need to change this to @RequestMapping("/run/") and in the jsp form action you may need to change <form id="myForm" action="/application/run/save" method="POST" accept="application/json" onclick="i()">, since you have defined @RequestMapping(value = "save", method = RequestMethod.POST, headers = {"content-type=application/json"}) for the 'save` method in the controller.

您可能需要在控制器的save方法中定义@RequestParam,如 public @ResponseBody Response save(@RequestParam(required = true,value =name)String name ,@ RequestBody用户)抛出异常{...}

You may need to define the @RequestParam in the save method in controller like public @ResponseBody Response save(@RequestParam(required=true, value="name") String name, @RequestBody User user) throws Exception {...}

因为它清楚说你的请求没有附加处理程序提交。

Since it clearly says that there is no handler attached to the request you are submitting.

这篇关于将JSON发送到Spring MVC控制器的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆