由括号外的逗号分隔的jQuery / JavaScript [英] jQuery/JavaScript Split String by Commas that are Outside of Parenthesis

问题描述

我正在使用jQuery& JavaScript !!

我有一个字符串，例如

  cubic-bezier（0.25,0,0.25,1），easy-in，ease-out，linear
  

..我想把它拆分成这个数组：

  //（以下没有前导或尾随空格： ）
 
数组[4] 
 0：cubic-bezier（0.25,0,0.25,1）
 1：轻松进入
 2：缓出
 3：线性
  

..但我得到：

 数组[7] 
 0：cubic-bezier（0.25 
 1：0 
 2：0.25 
 3 ：1）
 4：缓入
 5：缓出
 6：线性
  

我尝试了十几种解决方案，但却发现我尝试它的任何方式到目前为止都无效。以下是我以前的一些尝试：

  var myString =cubic-bezier（0.25,0,0.25,1），舒适，缓和，线性; 
 
 myString.split（，（？！[^ \（\）] *>））; 
 
 myString.split（'（？：\（。*？\））|（，）'）; 
 
 myString.split（，（？= [^ \]] *（？：\ [| $）））; 
 
 myString.split（，（？！[^（）] *（?: \（[^（）] * \））？\）））; 
 
 myString.split（'/，（？！[^（）] *（？：\（[^（）] * \））？\）/ g'）; 
 
 myString.split（，（？=（（[^'] *'）{2}）* [^'] * $）（？=（（[^ \] * \）{2}）* [^ \] * $）（？！[^（）] * \\）））; 
  

我熟悉基本的正则表达式规则，例如捕获组和选择器，但我仍然对前瞻或我如何解决当前情况感到困惑。

解决方案

匹配任何不在括号内的逗号

  var myString =cubic-bezier（0.25,0,0.25,1），ease-in，ease-out，linear; var parts = myString.split（/ \， \s /）？（[^ \（] * \）！）;执行console.log（份） 

  / \，\？？（？！[^ \（] * \））/ 
  

• \，匹配字符，字面意思


• \？匹配任何空格字符。？量词匹配0到1次


• （？！[^ \（] * \）） Negative Lookahead断言正则表达式与下面列表中不存在的单个字符不匹配


• [^ \（] 量词。在零和无限次之间匹配，尽可能多次


• \（匹配字符（字面意思


• \）匹配字符）字面意思

I am using jQuery & JavaScript!!

I have a string, for example

"cubic-bezier(0.25, 0, 0.25, 1), ease-in, ease-out, linear"

..and I want to split it into this array:

// (the following has no leading or trailing spaces:)

Array[4]
  0: cubic-bezier(0.25, 0, 0.25, 1)
  1: ease-in
  2: ease-out
  3: linear

..but instead I get:

Array[7]
  0: cubic-bezier(0.25
  1: 0
  2: 0.25
  3: 1)
  4: ease-in
  5: ease-out
  6: linear

I have attempted a dozen solutions, only to find that any way that I try it doesn't work thus far. Here are a few of my previous attempts:

var myString = "cubic-bezier(0.25, 0, 0.25, 1), ease-in, ease-out, linear";

myString.split(",(?![^\(\)]*>)");

myString.split('(?:\(.*?\))|(,)');

myString.split(",(?=[^\]]*(?:\[|$))");

myString.split(",(?![^()]*(?:\([^()]*\))?\))");

myString.split('/,(?![^()]*(?:\([^()]*\))?\)/g');

myString.split(",(?=(([^']*'){2})*[^']*$)(?=(([^\"]*\"){2})*[^\"]*$)(?![^()]*\\))");

I am familiar with basic regex rules, such as capture groups and selectors, but am still confused on lookaheads or how I would solve my current situation.

解决方案

Match any comma not inside parentheses

var myString = "cubic-bezier(0.25, 0, 0.25, 1), ease-in, ease-out, linear";

var parts    = myString.split(/\,\s?(?![^\(]*\))/);

console.log(parts)

/\,\s?(?![^\(]*\))/

• \, matches the character , literally
• \s? matches any whitespace character. The ? quantifier matches between zero and one times
• (?![^\(]*\)) Negative Lookahead asserts that the regex does not match a single character not present in the list below
• [^\(] Quantifier. Matches between zero and unlimited times, as many times as possible
• \( matches the character ( literally
• \) matches the character ) literally

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