将Google结果对象（纯js）转换为Python对象 [英] Convert Google results object (pure js) to Python object

问题描述

所以我正在尝试使用Google Map建议API来请求地名建议。不幸的是我找不到这个位的文档。

So I'm trying to use Google Map suggest API to request place name suggestions. Unfortunately I can't find the docs for this bit.

这是一个示例URI：

http://maps.google.com/maps/suggest?q=lon&cp=3&ll=55.0,-3.5&spn=11.9,1.2&hl=en& gl = uk& v = 2

返回：

{suggestion:[{query:"London",...

我想使用这在python（2.5）中。现在使用正确的JSON，键盘周围会有如下引用：

I want to use this in python (2.5). Now in proper JSON there would have been quotations around the keys like so:

{"suggestion":[{"query":"London",...

我可以使用simplejson或其他东西，但因为它是我有点卡住。

and I could have used simplejson or something, but as it is I'm a bit stuck.

这里有两种可能的解决方案;或者我可以获得API代码并找到返回正确JSON的选项，或者我在python中执行此操作。

There are two possible solutions here; either I can get to the API code and find an option to return proper JSON, or I do that in python.

请提出任何想法。

推荐答案

呃，这确实很烦人。这是一个JavaScript文字，但它 - 毫无意义 - 不是JSON。

Ugh, that's indeed pretty annoying. It's a JavaScript literal but it — pointlessly — isn't JSON.

理论上你应该能够导入 json.decoder.JSONDecoder 来自Python stdlib（或 simplejson pre-2.6，它是相同的）并将其子类化，然后将该子类传递给 json.loads 覆盖解码器行为。实际上这并不是真的可行，因为 json.decoder 充满了抵制子类化的全局交叉引用，你需要改变的位是slap bang in the middle of def JSONObject 。

In theory you are supposed to be able to import json.decoder.JSONDecoder from the Python stdlib (or simplejson pre-2.6, which is the same) and subclass it, then pass that subclass to json.loads to override decoder behaviour. In reality this isn't really feasible as json.decoder is full of global cross-references that resist subclassing, and the bit you need to change is slap bang in the middle of def JSONObject.

因此，可能值得查看其他Python JSON库。我发现这个，在'非严格'模式下，将解析不带引号的对象属性姓名：

So it's probably worth looking at other Python JSON libraries. I found this one which, in ‘non-strict’ mode, will parse unquoted object property names:

>>> import demjson
>>> demjson.decode('{suggestion:[{query:"London",interpretation: ...')
{u'suggestion': [{u'query': u'London', u'operation': 2, u'interpretation': ...

这篇关于将Google结果对象（纯js）转换为Python对象的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！