在javascript中执行php脚本？ [英] Executing a php script in javascript?

问题描述

当用户离开我的网站时，我正在尝试运行一个快速的PHP脚本，并且还将一个变量从我的javascript传递给php，但我不太确定如何包含php文件并将其传递给var。但它实际上并没有运行PHP脚本。任何想法？

I'm trying to run a quick php script when users leave my website, and also pass a variable from my javascript to php but i'm not quite sure how to include the php file and pass it a var. But it's not actually running the php script. any ideas?

（javascript从外部活动函数中获取用户名，我知道有效，我在一个警报及其那里测试了var。）

(the javascript gets the username from an external activity function, and i know that works i tested the var on an alert and its there.)

我的JavaScript：

My JavaScript:

<script language="javascript" type="text/javascript">

            var username = null;

            function GetUsername(usernameff)
            {
                username = usernameff;
            }

            window.onbeforeunload = function () 
            {

            if (username != null)
            {

            <?php include("scripts/RemoveUserOnDisconnect.php?username=username");?>
            }

            }


            </script>

我的RemoveUserOnDisconnect.php文件：

My RemoveUserOnDisconnect.php File:

<?php
    mysql_connect("mysql.mysql.com", "username", "password");
    mysql_select_db("my_db");
    mysql_query("DELETE FROM my_table WHERE username = '$username'");         
?>

推荐答案

尝试ajax请求。根据您的PHP脚本，您需要 $。发布或 $。获取

Try an ajax request. Depending on your php script you will need $.post or $.get

jQuery：

<script language="javascript" type="text/javascript">

    var username = null;

    function GetUsername(usernameff){
        username = usernameff;
    }

    window.onbeforeunload = function(){
        if (username != null){
          $.post('scripts/RemoveUserOnDisconnect.php', {username: username}, function(){
            //successful ajax request
          }).error(function(){
            alert('error... ohh no!');
          });

        }
    }
 </script>

编辑：

你的php脚本应该如果您使用我上面的代码，请参考 $ _ POST 数组。

Your php script should reference the $_POST array if you use my code above.

<?php
    $username = $_POST['username'];

    mysql_connect("mysql.mysql.com", "username", "password");
    mysql_select_db("my_db");
    mysql_query("DELETE FROM my_table WHERE username = '$username'");         
?>

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