JSLint“超出范围”功能排序导致的错误？ [英] JSLint "out of scope" error due to function ordering?

问题描述

JSLint似乎对功能排序很挑剔。

JSLint seems to be picky about function ordering.

这好转：

function a() {
    'use strict';
    return 1;
}

function b() {
    'use strict';
    a();
}

虽然这给出了'a'不在范围错误消息：

While this gives an 'a' is out of scope error message:

function b() {
    'use strict';
    a();
}

function a() {
    'use strict';
    return 1;
}

这是设计的吗？我应该关心吗？如何避免在较大（较复杂）的情况下避免给函数一个明确的顺序？

Is this by design? Should I care? How can it be avoided in larger (more complex) cases, where it might not always be possible to give the functions a clear order?

推荐答案

JSLint / JSHint希望您在引用它们之前定义函数。但是，JavaScript并不关心，因为函数和变量已悬挂。

JSLint/JSHint expect you to define functions before you reference them. However, JavaScript doesn't care because functions and variables are hoisted.

您可以使用 http://jshint.com/docs/options/#latedef

/* jshint latedef:nofunc */
function b() {
    'use strict';
    a();
}

function a() {
    'use strict';
    return 1;
}

参见 https://stackoverflow.com/a/23916719/227299

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