如何找到在javascript中按降序排序数字数组所需的最小交换次数 [英] How to find the Minimum number of swaps required for sorting an array of numbers in descending order in javascript
问题描述
我正在尝试让我的代码执行此操作:
原始数组= [1,2,3,4]交换一次 - > [4,2 ,3,1]再次交换 - > [4,3,2,1]
因此结果是2
<但是它不起作用。这是我到目前为止所拥有的:
function check(arr){var sarr = []; var cnt = 0; var arrL = arr.length; //创建数组的第二个副本以供参考var arrCopy = [... arr]; for(let i = 0; i< arrL; i ++){var maxV = Math.max(... arr); sarr.push(MAXV); let pos = arr.indexOf(maxV); //删除找到的号码arr.splice(pos,1); //检查新数组中的数字索引是否与副本相同,如果没有,那么有一个交换让ai = arrCopy.indexOf(maxV);设si = sarr.indexOf(maxV); if(ai!== si&&(i + 1)!= arrL&& pos!== 0){cnt ++; }; } console.log(cnt);} check([1,2,3,4,5,6]); //结果应为3check([6,5,4,3,2,1]); //结果应为0check([1,2,3,4]); //结果应为2check([1,3,2,5,4,6]); //结果应该是3check([1,2,10,4,5,6,7,8,9,3,12,11]); //结果应该是6check([49,37,9,19, 27,3,25,11,53,42,57,50,55,56,38,48,6,33,28,8,20,31,51,14,23,4,5,5,52,36, 22,41,47,39,2,7,13,45,1,42,32,10,15,21,30,17,60,29,5,59,12,40,24,54,46, 26,43,35,34,18,16]); //结果应为54
有人可以让我知道我做错了吗?
我会先说一个数组的副本按降序排列,以获得项目的正确索引。
出于实际原因,(或者只是包含检查和减少的循环的较短概念) ,我从数组的末尾循环。
然后我检查数组
和<$ c $的值c>在dame索引处反转并继续迭代。
如果不是相同的值,则需要位置的项目 i
和实际位置交换 p
并且计数递增。
最后返回计数。
function check(array){var reversed = array.slice()。sort((a,b) )=> b - a),count = 0,i = array.length,p; while(i--){if(array [i] === reversed [i])继续; p = array.indexOf(reverse [i]); [array [i],array [p]] = [array [p],array [i]];计数++; } console.log(... array); return count;} console.log(check([1,2,3,4,5,6])); // 3console.log(check([6,5,4,3,2,1])); // 0console.log(check([1,2,3,4])); // 2console.log(check([1,3,2,5,4,6])); // 3console.log(检查([1,2,10,4,5,6,7,8,9,3,12,11])); // 6console.log(检查([49,37,9,19,27,3,25,11,53,42,57,50,55,56,38,48,6,33,28,8,20] ,31,51,14,23,4,58,52,36,22,41,47,39,2,7,13,45,1,42,32,10,15,21,30,17,60 ,29,5,59,12,40,24,54,46,26,43,35,34,18,16])); // 54
.as-console-wrapper {max-身高:100%!重要;顶部:0; }
I'm trying to get my code to do this:
Original array = [1,2,3,4] swap once-> [4,2,3,1] swap again->[4,3,2,1]
Therefore result is 2
But it's not working. Here's what I have so far:
function check(arr){
var sarr = [];
var cnt = 0;
var arrL = arr.length;
// Create a second copy of the array for reference
var arrCopy = [...arr];
for(let i=0; i<arrL;i++){
var maxV = Math.max(...arr);
sarr.push(maxV);
let pos = arr.indexOf(maxV);
// Remove the found number
arr.splice(pos,1);
// Check if the index of the number in the new array is same with the copy, if not then there was a swap
let ai =arrCopy.indexOf(maxV);
let si =sarr.indexOf(maxV);
if (ai !== si && (i+1)!=arrL && pos !== 0){
cnt++;
};
}
console.log(cnt);
}
check([1, 2, 3, 4, 5, 6]);//Result should be 3
check([6,5,4,3,2,1]); //result should be 0
check([1,2,3,4]); //result should be 2
check([1,3,2,5,4,6]); //result should be 3
check([1,2,10,4,5,6,7,8,9,3,12,11]);//result should be 6
check([ 49, 37, 9, 19, 27, 3, 25, 11, 53, 42, 57, 50, 55, 56, 38, 48, 6, 33, 28, 8, 20, 31, 51, 14, 23, 4, 58, 52, 36, 22, 41, 47, 39, 2, 7, 13, 45, 1, 44, 32, 10, 15, 21, 30, 17, 60, 29, 5, 59, 12, 40, 24, 54, 46, 26, 43, 35, 34, 18, 16]);//result should be 54
Can someone please let me know what I'm doing wrong?
I would start with a copy of the array in descending order for getting the right index of the items.
For practical reasons, (or just a shorter conceprion of the loop with including check and decrement), i loop from the end of the array.
Then I check the value of array
and reversed
at the dame index and go on with the iteration.
If not the same value, the items at the wanted position i
and the actual position p
are swapped and the count incremented.
At the end the count is returned.
function check(array) {
var reversed = array.slice().sort((a, b) => b - a),
count = 0,
i = array.length,
p;
while (i--) {
if (array[i] === reversed[i]) continue;
p = array.indexOf(reversed[i]);
[array[i], array[p]] = [array[p], array[i]];
count++;
}
console.log(...array);
return count;
}
console.log(check([1, 2, 3, 4, 5, 6])); // 3
console.log(check([6, 5, 4, 3, 2, 1])); // 0
console.log(check([1, 2, 3, 4])); // 2
console.log(check([1, 3, 2, 5, 4, 6])); // 3
console.log(check([1, 2, 10, 4, 5, 6, 7, 8, 9, 3, 12, 11])); // 6
console.log(check([ 49, 37, 9, 19, 27, 3, 25, 11, 53, 42, 57, 50, 55, 56, 38, 48, 6, 33, 28, 8, 20, 31, 51, 14, 23, 4, 58, 52, 36, 22, 41, 47, 39, 2, 7, 13, 45, 1, 44, 32, 10, 15, 21, 30, 17, 60, 29, 5, 59, 12, 40, 24, 54, 46, 26, 43, 35, 34, 18, 16])); // 54
.as-console-wrapper { max-height: 100% !important; top: 0; }
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