正则表达式匹配单个括号对但不匹配双括号对 [英] Regular expression to match single bracket pairs but not double bracket pairs

问题描述

是否可以使正则表达式匹配单括号内的所有内容但忽略双括号，例如在：

Is it possible to make a regular expression to match everything within single brackets but ignore double brackets, so for example in:

{foo} {bar} {{baz}}

我想匹配foo和bar但不是baz？

I'd like to match foo and bar but not baz?

推荐答案

仅匹配 foo 和 bar 没有周围的大括号，你可以使用

To only match foo and bar without the surrounding braces, you can use

(?<=(?<!\{)\{)[^{}]*(?=\}(?!\}))

如果您的语言支持lookbehind断言。

if your language supports lookbehind assertions.

说明：

(?<=      # Assert that the following can be matched before the current position
 (?<!\{)  #  (only if the preceding character isn't a {)
\{        #  a {
)         # End of lookbehind
[^{}]*    # Match any number of characters except braces
(?=       # Assert that it's possible to match...
 \}       #  a }
 (?!\})   #  (only if there is not another } that follows)
)         # End of lookahead

编辑：在JavaScript中，您没有lookbehind。在这种情况下，您需要使用以下内容：

In JavaScript, you don't have lookbehind. In this case you need to use something like this:

var myregexp = /(?:^|[^{])\{([^{}]*)(?=\}(?!\}))/g;
var match = myregexp.exec(subject);
while (match != null) {
    for (var i = 0; i < match.length; i++) {
        // matched text: match[1]
    }
    match = myregexp.exec(subject);
}

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