Javascript占位符 [英] Javascript placeholders

查看:91
本文介绍了Javascript占位符的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我对javascript很陌生并且很挣扎。我的代码如下。使用更多代码更容易解​​释。所以基本上想要在每个占位符中显示每个图像,但是按照我点击它们的顺序。所以,如果我点击img 3,这将转到占位符1然后下一个我点击将转到占位符2,如果这是有道理的。 (这个棘手的位置是一旦选择了一个选项我想再次不允许该选项。或者有一个错误消息说已经使用过或从列表中消失)

I am really new to javascript and struggling big with it. The code i have is below. It's easier to explain with more code. So basically want to show each image in each placeholder but in the order i click them in. So if i click img 3 this will go to placeholder 1 then the next one i click will go to placeholder 2 if that makes sense. (this tricky bit is once one option has been chosen i want to not allow that option again. either with an error message saying already used or disappear from list)

    <script type="text/javascript" language="javascript">
function showPic (whichpic) { 
    if (document.getElementById) { 
        document.getElementById('placeholder1').src = whichpic.href;
        document.getElementById('placeholder2').src = whichpic.href;
        document.getElementById('placeholder3').src = whichpic.href;
        if (whichpic.title) { 
            document.getElementById('desc').childNodes[0].nodeValue = whichpic.title; 
        } else { 
            document.getElementById('desc').childNodes[0].nodeValue = whichpic.childNodes[0].nodeValue; 
        } 
        return false; 
    } else { 
        return true; 
    } 
}
</script>

<div style="border: 1px solid #999; padding: 1em; margin: 0 0 15px 0;">
<ul>
<li><a onclick="return showPic(this)" href="images/img1.jpg" title="img 1">img 1</a></li>
<li><a onclick="return showPic(this)" href="images/img2.jpg" title="img 2">img 2</a></li>
<li><a onclick="return showPic(this)" href="images/img3.jpg" title="img 3">img 3</a></li>
</ul>

<p id="desc">Choose an image to begin</p>
<img id="placeholder1" src="images/blank.gif" alt="" />
<img id="placeholder2" src="images/blank.gif" alt="" />
<img id="placeholder3" src="images/blank.gif" alt="" />
</div>


推荐答案

这取决于你的意思清单。如果你只是想检查src是否为空,你可以直接进行条件化:

That depends on what you mean by "something from the list". If you just want to check if the src is blank, you can do a direct conditional:

if (document.getElementById('placeholder1').src != '')
    document.getElementById('placeholder2').src = newurl;

这篇关于Javascript占位符的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆