按键及其项过滤对象 [英] filter object by key and its items
本文介绍了按键及其项过滤对象的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个对象,我想过滤它的键..
I have an object that I would like to filter it's keys..
我试图用ID过滤对象,如下所示:
Im trying to filter the object by an ID, like so:
let myKeys = Object.keys(data).filter(function(key) {
//console.log(data[key]);
if(parseInt(key) === parseInt(vm.system_id)) {
return data[key];
}
});
console.log(myKeys);
这部分工作 - 我获取密钥,但是,我没有得到所有的数据/项目此项目即时过滤
This works, partialy - im getting the key, however, im not getting all the data/items under this item im filtering out
对象即时过滤与此类似:
The object im filtering is one similar to this one:
{
"646": [{
"id": 52144,
"timestamp": "2017-08-17T14:10:23Z",
"type": "alarm",
"code": 210,
"title": "",
"description": "",
"remedy": "",
"appeared": "2017-08-17T14:10:09Z",
"disappeared": null,
"acknowlegded": null,
"solved": null,
"system_name": "CG-MX19D7K5C1",
"system_id": 646,
"system_device_id": 458,
"stream": "cu351.alarm_code"
}
],
"693": [{
"id": 51675,
"timestamp": "2017-08-16T13:59:55Z",
"type": "alarm",
"code": 215,
"title": "",
"description": "",
"remedy": "",
"appeared": "2017-08-16T13:59:57Z",
"disappeared": null,
"acknowlegded": null,
"solved": null,
"system_name": "Demo 07122016",
"system_id": 693,
"system_device_id": 371,
"stream": "cu351.alarm_code"
}, {
"id": 51677,
"timestamp": "2017-08-16T13:59:57Z",
"type": "alarm",
"code": 214,
"title": "",
"description": "",
"remedy": "",
"appeared": "2017-08-16T13:59:59Z",
"disappeared": null,
"acknowlegded": null,
"solved": null,
"system_name": "Demo 07122016",
"system_id": 693,
"system_device_id": 371,
"stream": "cu351.alarm_code"
}
]
}
推荐答案
数组#过滤器
期望一个布尔值作为返回值,你可以使用这个
Array#filter
is expecting a boolean value as return value, you might use this
let myKeys = Object.keys(data).filter(key => key == vm.system_id);
获取密钥然后使用给定密钥渲染新对象。
for getting the keys and then render a new object with the given keys.
要获取单个数组中的所有项目,您可以使用
To get all items in a single array, you could collect them with
let result = myKeys.reduce((r, k) => r.concat(data[k]), []);
这篇关于按键及其项过滤对象的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文